Mechanical Engineering - Engineering Mechanics - Discussion
Discussion Forum : Engineering Mechanics - Section 1 (Q.No. 36)
36.
The angle between two forces when the resultant is maximum and minimum respectively are
Discussion:
12 comments Page 1 of 2.
Azaruddin said:
4 years ago
Resultant is Maximum.
Cos(θ) = 1
θ = 0 degree.
Minimum,
Cos(θ) =-1
θ=180degree
Cos(θ) = 1
θ = 0 degree.
Minimum,
Cos(θ) =-1
θ=180degree
(2)
SHARANABASAVA said:
6 years ago
Thanks @Keyur Patel.
Saraki Yaman Alhaji said:
7 years ago
It should be 180° and 0°.
(1)
Uah said:
7 years ago
Thanks @Keyur Patel.
Lakhan bhavnani said:
7 years ago
Thanks @Keyur.
Shubham tambekar said:
7 years ago
Thanks @Keyur.
Keyur Patel said:
8 years ago
There is simple logic when two forces in same direction (0 degree) resultant is max. But they are opposite each other (180 degree) resultant force is min.
(1)
Ashish Mahajan said:
9 years ago
@Anil.
Your explanation is correct, only thing is that,
R = P - Q when theta is 180 degree.
Your explanation is correct, only thing is that,
R = P - Q when theta is 180 degree.
Aravibd said:
9 years ago
If θ = 0.
R = (P + Q)^2.
If θ =180.
R= (P-Q)^2.
Substitute values for p and q. We will get the answer.
R = (P + Q)^2.
If θ =180.
R= (P-Q)^2.
Substitute values for p and q. We will get the answer.
Patrick said:
9 years ago
I disagree. Applying cosine rule R^2 = P^2 + Q^2 - 2PQcos (theta).
Cos0 = 1 (which maintains a negative sign hence obtain a minimum value).
Cos180 = - 1 (which converts the negative sign to positive hence obtains a maximum value).
Cos0 = 1 (which maintains a negative sign hence obtain a minimum value).
Cos180 = - 1 (which converts the negative sign to positive hence obtains a maximum value).
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