Mechanical Engineering - Engineering Materials - Discussion
Discussion Forum : Engineering Materials - Section 2 (Q.No. 41)
41.
Pearlite consists of
Discussion:
3 comments Page 1 of 1.
Manoj said:
8 years ago
Option b is correct. I agree with the given answer.
Srikanth said:
8 years ago
Option C is the correct Answer
K.Harish (IIIT) said:
10 years ago
Pearlite forms at eutectoid reaction 727'c.
Austenite --------> ferrite + cementite.
= (0.77%c) (0.02%c) (6.67%c).
Ferrite percentage = ((6.67^\'0.77)*100)/(6.7-0.022) = 88.7%.
Cementite percentage = ((0.77-0.02)*100)/(6.7-0.022) = 11.3 %.
Austenite --------> ferrite + cementite.
= (0.77%c) (0.02%c) (6.67%c).
Ferrite percentage = ((6.67^\'0.77)*100)/(6.7-0.022) = 88.7%.
Cementite percentage = ((0.77-0.02)*100)/(6.7-0.022) = 11.3 %.
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