Mechanical Engineering - Automobile Engineering - Discussion

Simple formula.

Rr = Kr * W.
Where, Rr = Rolling Resistance (N)
Kr = Coefficient of Rolling Resistance.
W = Weight of the Vehicle (N).

So here,
W = 63500 N.
Kr = 0.018.
Rr=?
Put value in equation.
Rr = Kr * W.
= 0.018 *63 500.
Rr = 1143 N ==> Answer.

Coefficient of friction*weight.
= 63500*0.018 = 1143.

The rolling resistance can be expressed as;

Fr = c W ------> (1)

where

Fr = rolling resistance or rolling friction (N, lbf).
c = rolling resistance coefficient - dimensionless (coefficient of rolling friction - CRF).
W = m ag.
= normal force - or weight - of the body (N, lbf).
m = mass of body (kg, lb).
ag = acceleration of gravity (9.81 m/s2, 32.174 ft/s2).

The rolling resistance can alternatively be expressed as;

Fr = cl W / r ------> (2)

where

cl = rolling resistance coefficient - dimension length (coefficient of rolling friction) (mm, in)
r = radius of wheel (mm, in)

Good. Thanks for all the given explanation.

Truck weight = 63500N Coefficient Of Rolling resistance = 0.018 Rolling resistance = 0.18*63500N = 1143N.

Rolling Resistance R(r) = k(r)xW.

Where k(r) = co-efficient of rolling resistance (or) constant of rolling resistance.

f = mu * R.
R = W.

Truck weight = 63500N.
Coefficient of rolling resistance = 0.018.


Rolling resistance = 0.018 x 63500N = 1143N.

We know that,
Rolling resistance= Cofficient of rolling * weight.

According to question,
Truck weight = 63500 N.

Cofficient of rolling = 0.018.

Then,
Rolling resistence = 0.018*63500 = 1143 N

Truck weight = 63500N.
Coefficient of rolling resistance = 0.018.

Then,

Rolling resistance = 0.018 x 63500N = 1143N.