Java Programming - Language Fundamentals - Discussion
Discussion Forum : Language Fundamentals - Finding the output (Q.No. 1)
1.
What will be the output of the program?
public class CommandArgsThree
{
public static void main(String [] args)
{
String [][] argCopy = new String[2][2];
int x;
argCopy[0] = args;
x = argCopy[0].length;
for (int y = 0; y < x; y++)
{
System.out.print(" " + argCopy[0][y]);
}
}
}
and the command-line invocation is
> java CommandArgsThree 1 2 3
Answer: Option
Explanation:
In argCopy[0] = args;, the reference variable argCopy[0], which was referring to an array with two elements, is reassigned to an array (args) with three elements.
Discussion:
36 comments Page 4 of 4.
Dima said:
1 decade ago
Where is the first space character?
Abhijit said:
1 decade ago
Can anyone explain how is it come?
John said:
2 years ago
Please explain the answer clearly.
(1)
Eric said:
1 decade ago
How do I invoke the command line?
Ravindra said:
1 decade ago
How it is possible ?
Disha said:
1 decade ago
Please explain me.
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