Java Programming - Language Fundamentals - Discussion

Discussion Forum : Language Fundamentals - Finding the output (Q.No. 1)
1.
What will be the output of the program?
public class CommandArgsThree 
{
    public static void main(String [] args) 
    {
        String [][] argCopy = new String[2][2];
        int x;
        argCopy[0] = args;
        x = argCopy[0].length;
        for (int y = 0; y < x; y++) 
        {
            System.out.print(" " + argCopy[0][y]);
        }
    }
}

and the command-line invocation is

> java CommandArgsThree 1 2 3

0 0
1 2
0 0 0
1 2 3
Answer: Option
Explanation:
In argCopy[0] = args;, the reference variable argCopy[0], which was referring to an array with two elements, is reassigned to an array (args) with three elements.
Discussion:
36 comments Page 3 of 4.

Jyothi said:   1 decade ago
Can anyone explain this clearly because I don't know java.

I'm trying to analyse using C. Help me out.

Cat said:   1 decade ago
As I don't know anything about java so please explain me clearly. Don't hesitate to help me.

Sonal Bhutada said:   1 decade ago
I m not able to understand. Please explain it in a much easier way.

Surbhi said:   5 years ago
Thank you so much for explaining. It's very useful.
(2)

Anita said:   1 decade ago
Here argcopy declared within 2 dimensional array.

P .naresh said:   1 decade ago
What is the basic programming structure of java?

Sharma said:   8 years ago
I can't understand. How output will 1, 2, 3?

Nikhil said:   10 years ago
Please anyone explain code line by line.

USHA said:   10 years ago
Please explain me with simple example.

Eric said:   1 decade ago
How do I get this program to execute?


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