Java Programming - Declarations and Access Control - Discussion
Discussion Forum : Declarations and Access Control - Finding the output (Q.No. 5)
5.
What will be the output of the program?
public class Test
{
public int aMethod()
{
static int i = 0;
i++;
return i;
}
public static void main(String args[])
{
Test test = new Test();
test.aMethod();
int j = test.aMethod();
System.out.println(j);
}
}
Answer: Option
Explanation:
Compilation failed because static was an illegal start of expression - method variables do not have a modifier (they are always considered local).
Discussion:
14 comments Page 2 of 2.
Bhargavi said:
1 decade ago
Static variables cannot be instantiated and it could be accessed only by class-name.
Vinodkumar said:
1 decade ago
When we use static it binds with class but there we are using static inside of non-static method so it won't bind with class because we got compilation error.
Archana said:
1 decade ago
We cannot access non-static methods in static method.
Vimmi said:
1 decade ago
There are so many answers here but the correct is Static variables cannot be local variable in java.
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