Java Programming - Declarations and Access Control - Discussion
Discussion Forum : Declarations and Access Control - Finding the output (Q.No. 5)
5.
What will be the output of the program?
public class Test
{
public int aMethod()
{
static int i = 0;
i++;
return i;
}
public static void main(String args[])
{
Test test = new Test();
test.aMethod();
int j = test.aMethod();
System.out.println(j);
}
}
Answer: Option
Explanation:
Compilation failed because static was an illegal start of expression - method variables do not have a modifier (they are always considered local).
Discussion:
14 comments Page 2 of 2.
Raju said:
1 decade ago
The integer value returned is not obtained in any variable.
Is it not an error?
Is it not an error?
Manish said:
1 decade ago
We can only have final variable as local.
Kapil said:
1 decade ago
Static variables can only be declared as Global Variables (not local).
Dinu said:
2 decades ago
This not the correct explanation yaar
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers