General Knowledge - Physics - Discussion
Discussion Forum : Physics - Section 1 (Q.No. 79)
79.
An aeroplane is flying horizontally with a velocity of 600 km/h and at a height of 1960 m. When it is vertically at a point A on the ground a bomb is released from it. The bomb strikes the ground at point B. The distance AB is
Discussion:
36 comments Page 2 of 4.
Vinod choudhary said:
9 years ago
Given data-
velocity (v) = 600km/h = (600x1000)/3600.
v = 166.66m/s.
Height (h) = 1960m.
We know that, the second law of motion.
s = ut + 0.5 * a *t * t----> 1
Put the given values in equation (1)
1960 = (0xt)+(0.5xtxt).
t(square) = 1960/0.5
t = 20 sec.
But again we know that velocity = distance/time.
v = d/t,
d = (v) * (t),
d = 20 * 166.66,
d = 3333.2m,
d = 3333.2/1000 = 3.33 km.
Ans. (d) = 3.33 km.
velocity (v) = 600km/h = (600x1000)/3600.
v = 166.66m/s.
Height (h) = 1960m.
We know that, the second law of motion.
s = ut + 0.5 * a *t * t----> 1
Put the given values in equation (1)
1960 = (0xt)+(0.5xtxt).
t(square) = 1960/0.5
t = 20 sec.
But again we know that velocity = distance/time.
v = d/t,
d = (v) * (t),
d = 20 * 166.66,
d = 3333.2m,
d = 3333.2/1000 = 3.33 km.
Ans. (d) = 3.33 km.
Maloni said:
8 years ago
@Vinod.
May I know why didn't you put the value of acceleration while using 2nd law of motion equation.
May I know why didn't you put the value of acceleration while using 2nd law of motion equation.
Peter smart said:
8 years ago
physics keeps me always in motion
Alhussain said:
7 years ago
Why isn't the time 20secs when we use the formula: V=U+at?
Mustapha Daniel said:
7 years ago
Because it does not deal with height in the equation.
Yoga said:
5 years ago
What is a projectile of motion?
Shanu said:
3 years ago
They haven't mentioned the time.
Then how did you guys calculate the projectile motion? Please explain me.
Then how did you guys calculate the projectile motion? Please explain me.
Wqwjjj said:
2 years ago
I'm not getting this. Please explain me in detail.
Navin chahar said:
1 decade ago
What is projectile motion and not sure about this question?
S RAMKIRAN said:
1 decade ago
Solution: see in the question its given:
Velocity= 600Km/hr = 600x1000/3600 m/s=166.66m/s
Ht=1960m.
To Find: The range of the projectile (R).
Its actually a Projetile motion .
For a projectile Ht=1/2*g*t*t.There fore we get t= 20s.
R=V*t=166.66*20=3333.33m/s=3.333Km/hr.
Velocity= 600Km/hr = 600x1000/3600 m/s=166.66m/s
Ht=1960m.
To Find: The range of the projectile (R).
Its actually a Projetile motion .
For a projectile Ht=1/2*g*t*t.There fore we get t= 20s.
R=V*t=166.66*20=3333.33m/s=3.333Km/hr.
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