General Knowledge - Physics - Discussion
Discussion Forum : Physics - Section 1 (Q.No. 79)
79.
An aeroplane is flying horizontally with a velocity of 600 km/h and at a height of 1960 m. When it is vertically at a point A on the ground a bomb is released from it. The bomb strikes the ground at point B. The distance AB is
Discussion:
36 comments Page 1 of 4.
Wqwjjj said:
2 years ago
I'm not getting this. Please explain me in detail.
Shanu said:
3 years ago
They haven't mentioned the time.
Then how did you guys calculate the projectile motion? Please explain me.
Then how did you guys calculate the projectile motion? Please explain me.
Nas said:
3 years ago
@Tamil Nayagam,
1960/600 = 3.266.
We can take 3.3.
1960/600 = 3.266.
We can take 3.3.
(1)
Yoga said:
5 years ago
What is a projectile of motion?
Matiur Rahamam said:
7 years ago
Convert velocity in horizontal direction, Ux into m/s:
Ux = 600x1000/3600 = 500/3 m/s.
Velocity of the bomb during the flight is constant due to inertia. Therefore,
Initial velocity in vertical direction, Uy = 0,
Height = 1960 m.
Step 2: Find time 't' using the equation [s = ut + 1/2at^2]
Replace distance 's' by height 'h' and acceleration 'a' by gravity 'g'
h = 1/2gt^2
t = √(2h)/g = √(2x 1960/9.8) = 20 sec.
Step 3: Find the distance traversed by the bomb in horizontal direction:
Distance AB = vx t = 500/3 x 20 = 10/3 x 10^3m = 3.333 km.
Ux = 600x1000/3600 = 500/3 m/s.
Velocity of the bomb during the flight is constant due to inertia. Therefore,
Initial velocity in vertical direction, Uy = 0,
Height = 1960 m.
Step 2: Find time 't' using the equation [s = ut + 1/2at^2]
Replace distance 's' by height 'h' and acceleration 'a' by gravity 'g'
h = 1/2gt^2
t = √(2h)/g = √(2x 1960/9.8) = 20 sec.
Step 3: Find the distance traversed by the bomb in horizontal direction:
Distance AB = vx t = 500/3 x 20 = 10/3 x 10^3m = 3.333 km.
(6)
Mustapha Daniel said:
7 years ago
Because it does not deal with height in the equation.
Alhussain said:
7 years ago
Why isn't the time 20secs when we use the formula: V=U+at?
Peter smart said:
8 years ago
physics keeps me always in motion
Diptikanta sahu said:
8 years ago
What is a projectile of motion?
(1)
Bave said:
8 years ago
First. We will change m/s.
Then 600 * 1000/3600 = 166.666m/s.
Next. H=1/2at^2.so 1960=1/2*9.8*t^2.
Then t=20s.
Finally, Use H=ut equation.then H=166.66 * 20.
So 3333.333metres.
So answer 3.33km.
Then 600 * 1000/3600 = 166.666m/s.
Next. H=1/2at^2.so 1960=1/2*9.8*t^2.
Then t=20s.
Finally, Use H=ut equation.then H=166.66 * 20.
So 3333.333metres.
So answer 3.33km.
(1)
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