General Knowledge - Physics - Discussion
Discussion Forum : Physics - Section 1 (Q.No. 79)
79.
An aeroplane is flying horizontally with a velocity of 600 km/h and at a height of 1960 m. When it is vertically at a point A on the ground a bomb is released from it. The bomb strikes the ground at point B. The distance AB is
Discussion:
36 comments Page 4 of 4.
Umar said:
1 decade ago
SOLUTION:
Velocity = 600km/hr=600*1000/3600m/s.
= 166.66m/s.
FORMULA:
Ht = 0.5*a*t*t.
Ht = 0.5*9.8*2*2.
Ht = 19.6+0.4.
H t= 20 seconds.
R = V*t.
R = 166.66*20 SEC.
R = 333.2km.
R = 333.2/1000.
R = 3.33km.
Therefore R is 3.33km.
Velocity = 600km/hr=600*1000/3600m/s.
= 166.66m/s.
FORMULA:
Ht = 0.5*a*t*t.
Ht = 0.5*9.8*2*2.
Ht = 19.6+0.4.
H t= 20 seconds.
R = V*t.
R = 166.66*20 SEC.
R = 333.2km.
R = 333.2/1000.
R = 3.33km.
Therefore R is 3.33km.
Tushar said:
1 decade ago
When a body is projected into space and no longer propelled by fuel and other external forces except gravity it's motion is called a projectile motion.
Tamil nayagam.g said:
1 decade ago
1960/600 = 33.2666666666667.
Rajat shukla said:
10 years ago
Why is initial velocity 0? Why not 600 as plane is moving at 600?
Rajat shukla said:
10 years ago
Why is initial velocity not 600?
Rajat shukla said:
10 years ago
When body travels under the effect of gravity and when initial velocity g are not at 180 to each other i.e opposite then projectile motion in which the body follows a curved path.
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