General Knowledge - Physics - Discussion
Discussion Forum : Physics - Section 1 (Q.No. 46)
46.
Sound produced at a point is heard by a person after 5 second, while the same sound is heard by another person after 6 seconds. If the speed of sound is 300 m/s, what could be the maximum and minimum distances between the two persons?
Discussion:
17 comments Page 1 of 2.
Mani said:
2 decades ago
How to obtain this?
Nalin said:
1 decade ago
PLease can you give a solution for this question
Dhivya said:
1 decade ago
Can you say the formula to be used to get the solution ? please!
Anu paaras said:
1 decade ago
Time difference of 2 persons is 1sec, it means distance between them is 300 m which is 3.3km, so option D is correct.
HARISH said:
1 decade ago
Use the formula DISTANCE = SPEED * TIME TAKEN.
For MAX add both & for MIN sub both.
For MAX add both & for MIN sub both.
Vamshikrishna said:
1 decade ago
DISTANCE = SPEED * TIME TAKEN
d1=300*5=1500
d2=300*6=1800
maximum distance=d1+d2
=1500+1800
=3300 metres=3.3km
minimum distance=d2-d1
=1800-1500
=300 metres=0.3km
d1=300*5=1500
d2=300*6=1800
maximum distance=d1+d2
=1500+1800
=3300 metres=3.3km
minimum distance=d2-d1
=1800-1500
=300 metres=0.3km
Anita said:
1 decade ago
Maximum distance = speed * time
= 300 * (6+5)
= 300 * 11
= 3300 m
= 3.3 km
Minimum distance = speed * time
= 300 * (6-5)
= 300 * 1
= 300 m
= 0.3 km
= 300 * (6+5)
= 300 * 11
= 3300 m
= 3.3 km
Minimum distance = speed * time
= 300 * (6-5)
= 300 * 1
= 300 m
= 0.3 km
Sheela said:
1 decade ago
Distance of first person from the object: 300*5 = 1500 m=1.5km
Distance of second person from the object: 300*6 = 1800 m=1.8km
Max distance will be 1.5+1.8 =3.3 km (both are in opposit directions)
Min. distance will be 1.8-1.5 = 0.30 km (both are in same direction)
Distance of second person from the object: 300*6 = 1800 m=1.8km
Max distance will be 1.5+1.8 =3.3 km (both are in opposit directions)
Min. distance will be 1.8-1.5 = 0.30 km (both are in same direction)
Vivetha.h said:
1 decade ago
Distance=speed *Time
Distance(max)=1.8+0.15=1.95
Distance(min)=1.8-0.15=1.65
=1.95-1.65=0.3km
Distance(max)=1.8+0.15=1.95
Distance(min)=1.8-0.15=1.65
=1.95-1.65=0.3km
Raymart S. Estabaya said:
1 decade ago
Given: speed=300 m/s
time 1= 5s
time 2= 6s
Remember that: Speed=distance/time
So,given the speed and the time.
SOLUTION:
Distance=(speed)x(time)
D1=(300 m/s)x(5s)
=1500m note:time unit(second was cancelled)
D2=(300 m/s)x(6s)
=1800m
MAX: D1 + D2
1500m+1800m
=3300m or 3.3km
MIN: D2-D2
=1800m-1500m
=300m or 0.3 km
time 1= 5s
time 2= 6s
Remember that: Speed=distance/time
So,given the speed and the time.
SOLUTION:
Distance=(speed)x(time)
D1=(300 m/s)x(5s)
=1500m note:time unit(second was cancelled)
D2=(300 m/s)x(6s)
=1800m
MAX: D1 + D2
1500m+1800m
=3300m or 3.3km
MIN: D2-D2
=1800m-1500m
=300m or 0.3 km
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