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Discussion Forum : General Science - Nuclear Science (Q.No. 10)
10.
What is the wavelength of visible spectrum?
Discussion:
6 comments Page 1 of 1.
Varas said:
9 years ago
The range is 390nm to 760nm...it is correct...
For conversion 1nm =10^("9)m. And 1 angst rom =10^ (-10)m.
So, 1nm= 10^(-9)m = 10^ (-10 + 1) m = 10^ (-10)m * 10^ (1) m. = 1angstrom * 10 = 10 angstrom.
Finally 1 nm = 10 angstrom
For conversion 1nm =10^("9)m. And 1 angst rom =10^ (-10)m.
So, 1nm= 10^(-9)m = 10^ (-10 + 1) m = 10^ (-10)m * 10^ (1) m. = 1angstrom * 10 = 10 angstrom.
Finally 1 nm = 10 angstrom
Manasa said:
9 years ago
Please expain it.
Gayu said:
9 years ago
Me also can not understand, please you explain sir,
Shifin said:
1 decade ago
@Satish.
Can you explain a little more about unit conversion? I can not understand it well.
Can you explain a little more about unit conversion? I can not understand it well.
Satish said:
1 decade ago
Actually wavelength of visible spectrum is 390nm to 760nm.
But in this case wavelength is in angstrom units.So, 1nm=10^-9.
1angstrom=10^10.By converting nanometers to angstroms it is between 3900 to 7600.So answer to be option C.
But in this case wavelength is in angstrom units.So, 1nm=10^-9.
1angstrom=10^10.By converting nanometers to angstroms it is between 3900 to 7600.So answer to be option C.
Arvind said:
1 decade ago
plz! give me solution
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