General Knowledge - Chemistry - Discussion
Discussion Forum : Chemistry - Section 1 (Q.No. 71)
71.
Equal masses of oxygen, hydrogen and methane are kept under identical conditions. The ratio of the volumes of gases will be
Discussion:
9 comments Page 1 of 1.
Siva Rama Krishna said:
8 years ago
Thank you @Thangarasu.
Kuldeep said:
8 years ago
Equal molecules occupy equal volume.
So, the answer should be A, as molecules ratio is 2:16:2.
So, the answer should be A, as molecules ratio is 2:16:2.
Sakshi panwar said:
10 years ago
Please give explanation for this question.
(1)
Pallab said:
1 decade ago
Because L.C.M of 32, 2 and 16 is 32.
Abhi. said:
1 decade ago
Why multiply 32?
Naimish verma said:
1 decade ago
Depend on the molecular weight if lighter then occupied more volume vice versa.
ASHUTOSH KUMAR GAURAV said:
1 decade ago
SINCE PV = NRT = (m/M)RT.
SO V IS DIRECTLY PROPORTIONAL TO m/M.
OXYGEN:HYDROGEN:METHANE.
1/32:1/2:1:16.
MULTIPLYING BY 32,
1:16:2.
SO V IS DIRECTLY PROPORTIONAL TO m/M.
OXYGEN:HYDROGEN:METHANE.
1/32:1/2:1:16.
MULTIPLYING BY 32,
1:16:2.
(3)
Sss said:
1 decade ago
(m/32P)RT :(m/2P)RT : (m/16P)RT
P.Thangarasu said:
1 decade ago
PV=(m/M)RT
V=(m/MP)RT
02 : H2 CH4
(m/36P)RT :(m/2P)RT : (m/16P)RT
1/32 : 1/2 : 1/16
1:16:2
V=(m/MP)RT
02 : H2 CH4
(m/36P)RT :(m/2P)RT : (m/16P)RT
1/32 : 1/2 : 1/16
1:16:2
(1)
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