General Knowledge - Chemistry - Discussion

I think the answer is correct because after D, orbital looses their one electron it stabilised fully.

I think the answer is B because, when its Mg=12, it is 1s2 2s2 2p6 3S2 but the Fe=26 is 1s2 2s2 2p6 3s2 3p6 4s2 3D6.

Even after you lose one electron from the 'd' of Fe orbital it still is not equal to that of Mg.

Answer must be option C) Fe (26).

Neon is a gas (group 8), Valence electron - 2. Mg and Friday are electro positive metals +2. Click is not equal because it has - 1(2, 8 7). The answer is done.

Please give the correct answer description.

The electron configurations are as follows:

1. **Fe²⁺ (Z = 26):** [Ar] 3d⁶.
=> The number of d-electrons is 6.

2. **Ne (Z = 10):** 1s² 2s² 2p⁶
=> There are no p-electrons in Ne.

3. **Mg (Z = 12):** 1s² 2s² 2p⁶ 3s²
=> The number of s-electrons is 2.

4. **Fe (Z = 26):** [Ar] 4s² 3d⁶
=> The number of d-electrons is 6.

5. **Cl (Z = 17):** 1s² 2s² 2p⁶ 3s² 3p⁵
=> The number of p-electrons is 5.

In summary:

- The number of d-electrons in Fe²⁺ (Z = 26) is **6**.
- The number of p-electrons in Ne (Z = 10) is **0**.
- The number of s-electrons in Mg (Z = 12) is **2**.
- The number of d-electrons in Fe (Z = 26) is **6**.
- The number of p-electrons in Cl (Z = 17) is **5**.

Therefore, the statement is correct.

The number of d-electrons in Fe²⁺ is not equal to the specified electron counts in Ne, Mg, Fe, and Cl.

For 26= 1s2,2s2,2p6,3s2,3p6,4s2,3d6.
So d electron = 6.
For 10 = 1s2,2s2,2p6. So p electron = 6
For 12 = 1s2,2s2,2p6,3s2. So s electron = 6
And for 17= 1s2,2s2,2p6,3s2,3p5. So p electron = 11
So option d is different.

Number of d-electrons in Fe2+ and number of p-orbitals in Cl are same...

What is the molar mass of hydrogen H2?

After seeing explains, I don't think any other explanation is required.