General Knowledge - Chemistry - Discussion

Discussion Forum : Chemistry - Section 1 (Q.No. 51)
51.
The ionisation energy of hydrogen atom in the ground state is x KJ. The energy required for an electron to jump from 2nd orbit to 3rd orbit is
5x/36
5x
7.2 x
x/6
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
15 comments Page 2 of 2.

Rakesh said:   8 years ago
I can't understand this.

Kani said:   7 years ago
Can anyone explain this?

Nisarga ram said:   6 years ago
I can't understand please can anyone explain this.

Ramesh v said:   6 years ago
we know that E=X(1/M^2*1/N^2), where M=2,N=3 putting this value of M,N so,
E=x(1/2*1/3^2)
E=x(1/4-1/9).

E=x (9-4)/36.
E =x.5/36=5x/36 answer.
(2)

Godfred said:   3 years ago
I'm confused. Please explain in more detail.


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