General Knowledge - Chemistry - Discussion
Discussion Forum : Chemistry - Section 1 (Q.No. 51)
51.
The ionisation energy of hydrogen atom in the ground state is x KJ. The energy required for an electron to jump from 2nd orbit to 3rd orbit is
Discussion:
15 comments Page 2 of 2.
Dania said:
1 decade ago
Can't understand this?
Clint said:
1 decade ago
From Rydberg's:
x{[1/(2^2)] - [1/(3^2)]} = 5x/36.
x{[1/(2^2)] - [1/(3^2)]} = 5x/36.
Vishnu said:
1 decade ago
Energy of electron transition depends on the principle quantum numbers.
ie: 1/n1square - 1/n2square.
Here n1=2, n2 =3.
ie: 1/n1square - 1/n2square.
Here n1=2, n2 =3.
(1)
Kirtijain said:
1 decade ago
Please explain how this calculation is done ?
Rohit chauhan said:
1 decade ago
Could anybody explain me this question?
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