Engineering Mechanics - Structural Analysis - Discussion

Discussion :: Structural Analysis - General Questions (Q.No.2)

2. 

The principles of a differential chain block are indicated schematically in the figure. Determine the magnitude of force P needed to support the 800-N force. Also compute the distance x where the cable must be attached to bar AB so the bar remains horizontal. All pulleys have a radius of 60 mm.

[A]. P = 80 N, x = 240 mm
[B]. P = 80 N, x = 180 mm
[C]. P = 40 N, x = 180 mm
[D]. P = 40 N, x = 240 mm

Answer: Option D

Explanation:

No answer description available for this question.

Student said: (Aug 28, 2012)  
Please explain this problem

Ameet Kumar said: (Apr 26, 2016)  
Please explain this question and solution.

Ismayil said: (Mar 6, 2017)  
At Left block.
Each rope on left block 800/4=200N.
Last rope also is equal 200N.

At Right block:
Same principle,
P=200/5=40N.

Let's call left block top line joint points A, B(hook point), C, D.
B=200.
Each Pulley point load is 40+40=80N.
C=80.
D=80.
sum of M(A)=0.
200 * x - 180 * 80 - 420 * 80 = 0.
200 * x = 48000.
x = 240mm.
Good luck.

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