Engineering Mechanics - Structural Analysis - Discussion
Discussion Forum : Structural Analysis - General Questions (Q.No. 2)
2.
The principles of a differential chain block are indicated schematically in the figure. Determine the magnitude of force P needed to support the 800-N force. Also compute the distance x where the cable must be attached to bar AB so the bar remains horizontal. All pulleys have a radius of 60 mm.
Discussion:
4 comments Page 1 of 1.
MERCY said:
3 years ago
Please explain this.
Ismayil said:
8 years ago
At Left block.
Each rope on left block 800/4=200N.
Last rope also is equal 200N.
At Right block:
Same principle,
P=200/5=40N.
Let's call left block top line joint points A, B(hook point), C, D.
B=200.
Each Pulley point load is 40+40=80N.
C=80.
D=80.
sum of M(A)=0.
200 * x - 180 * 80 - 420 * 80 = 0.
200 * x = 48000.
x = 240mm.
Good luck.
Each rope on left block 800/4=200N.
Last rope also is equal 200N.
At Right block:
Same principle,
P=200/5=40N.
Let's call left block top line joint points A, B(hook point), C, D.
B=200.
Each Pulley point load is 40+40=80N.
C=80.
D=80.
sum of M(A)=0.
200 * x - 180 * 80 - 420 * 80 = 0.
200 * x = 48000.
x = 240mm.
Good luck.
Ameet kumar said:
9 years ago
Please explain this question and solution.
Student said:
1 decade ago
Please explain this problem
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