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Engineering Mechanics - Kinematics of Particle (KOP) - Discussion

Discussion Forum : Kinematics of Particle (KOP) - General Questions (Q.No. 6)
Kinematics of Particle (KOP)
6.

A passenger in the automobile B observes the motion of the train car . At the instant shown, the train has a speed of 18 m/s and is reducing its speed at a rate of 1.5 m/s2. The automobile is accelerating at 2 m/s2 and has a speed of 25 m/s. Determine the velocity and acceleration of A with respect to B. The train is moving along a curve of radius = 300 m.

vA/B = (25.0i+18.00j) m/s, aA/B = (2.00i-1.500j) m/s2
vA/B = (25.0i+18.00j) m/s, aA/B = (0.920i-1.500j) m/s2
vA/B = (-25.0i-18.00j) m/s, aA/B = (-2.00i+1.500j) m/s2
vA/B = (-25.0i-18.00j) m/s, aA/B = (-0.920i+1.500j) m/s2
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
4 comments Page 1 of 1.
Nagesh said:   3 years ago
Please explain the step of the calculation.
JOHNN said:   7 years ago
How to solve this problem? Please explain the steps.
Abel said:   9 years ago
How to solve this problem? Please explain the steps.
Rohit kumar said:   1 decade ago
Train is moving in circle so it has 2 accelerations. One along tangent and one along center. So in calculating relative acceleration we have to consider both acceleration of train in x and y direction which is centripetal and tangential acceleration simultaneously.
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