Engineering Mechanics - Kinematics of Particle (KOP) - Discussion
Discussion Forum : Kinematics of Particle (KOP) - General Questions (Q.No. 20)
20.
A ball is thrown downward on the 30° inclined plane so that when it rebounds perpendicular to the incline it has a velocity of vA = 40 ft/s. Determine the distance R where it strikes the plane at B.
Discussion:
3 comments Page 1 of 1.
Abhishek Anand said:
9 years ago
In this question 'g' is to be taken is 3ft/s^2.
Abhishek Anand said:
9 years ago
If we take x-axis as inclined plane and y-axis normal to it upward.
Then using Sy = Uy + ayt^2/2.
Here, Sy = 0, Uy = 40 and ay = -gcos30 we will get value of t^2.
Now Sx = Ux + axt^2/2, where Ux = 0, ax = gsin30 and we know t^2. So we will get Sx which is R = 69.28ft(g = 10m/s^2).
Then using Sy = Uy + ayt^2/2.
Here, Sy = 0, Uy = 40 and ay = -gcos30 we will get value of t^2.
Now Sx = Ux + axt^2/2, where Ux = 0, ax = gsin30 and we know t^2. So we will get Sx which is R = 69.28ft(g = 10m/s^2).
Kumara swamy said:
9 years ago
I think the correct answer may be 217.465.
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