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Engineering Mechanics - Kinematics of Particle (KOP) - Discussion

Discussion Forum : Kinematics of Particle (KOP) - General Questions (Q.No. 10)
Kinematics of Particle (KOP)
10.

A car, initially at rest, moves along a straight road with constant acceleration such that it attains a velocity of 60 ft/s when s = 150 ft. Then after being subjected to another constant acceleration, it attains a final velocity of 100 ft/s when s = 325 ft. Determine the average velocity and average acceleration of the car for the entire 325-ft displacement.

vavg = 80.0 ft/s, aavg = 15.15 ft/s2
vavg = 45.2 ft/s, aavg = 13.91 ft/s2
vavg = 80.0 ft/s, aavg = 12.57 ft/s2
vavg = 55.0 ft/s, aavg = 15.15 ft/s2
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
3 comments Page 1 of 1.
Shubham. said:   5 years ago
How to find the time? Please explain.
Kumara swamy said:   9 years ago
Average acceleration= (vf - vi)/total time.

Total time = 5 + 2.1875 = 7.1875.

Vf = 100, vi = 0.

Acceleration = 100/7.1875 = 13.913.
Yemane said:   9 years ago
How to find the acceleration?
(1)
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