Engineering Mechanics - Kinematics of Particle (KOP) - Discussion

Discussion :: Kinematics of Particle (KOP) - General Questions (Q.No.10)

10. 

A car, initially at rest, moves along a straight road with constant acceleration such that it attains a velocity of 60 ft/s when s = 150 ft. Then after being subjected to another constant acceleration, it attains a final velocity of 100 ft/s when s = 325 ft. Determine the average velocity and average acceleration of the car for the entire 325-ft displacement.

[A]. vavg = 80.0 ft/s, aavg = 15.15 ft/s2
[B]. vavg = 45.2 ft/s, aavg = 13.91 ft/s2
[C]. vavg = 80.0 ft/s, aavg = 12.57 ft/s2
[D]. vavg = 55.0 ft/s, aavg = 15.15 ft/s2

Answer: Option B

Explanation:

No answer description available for this question.

Yemane said: (Apr 30, 2016)  
How to find the acceleration?

Kumara Swamy said: (Jun 1, 2016)  
Average acceleration= (vf - vi)/total time.

Total time = 5 + 2.1875 = 7.1875.

Vf = 100, vi = 0.

Acceleration = 100/7.1875 = 13.913.

Shubham. said: (Jul 3, 2020)  
How to find the time? Please explain.

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