Engineering Mechanics - Kinematics of Particle (KOP) - Discussion
Discussion Forum : Kinematics of Particle (KOP) - General Questions (Q.No. 33)
33.
A small metal particle passes downward through a fluid medium while being subjected to the attraction of a magnetic field such that its position is observed to be s = (15t3 - 3t) mm, where t is measured in seconds. Determine (a) the particle's displacement from t = 2 s to t = 4 s, and (b) the velocity and acceleration of the particle when t = 5 s.
s = 834 mm, v = 1122 mm/s, a = 450 mm/s2 s = 114 mm, v = 1122 mm/s, a = 450 mm/s2 s = 114 mm, v = 450 mm/s, a = 1122 mm/s2 s = 834 mm, v = 450 mm/s, a = 1122 mm/s2Discussion:
2 comments Page 1 of 1.
Dheejay said:
1 decade ago
How do you get the velocity and acceleration please?
Kumara swamy said:
7 years ago
v=ds/dt and a=dv/dt just differentiate.
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