Engineering Mechanics - Kinematics of Particle (KOP) - Discussion

Discussion :: Kinematics of Particle (KOP) - General Questions (Q.No.33)

33. 

A small metal particle passes downward through a fluid medium while being subjected to the attraction of a magnetic field such that its position is observed to be s = (15t3 - 3t) mm, where t is measured in seconds. Determine (a) the particle's displacement from t = 2 s to t = 4 s, and (b) the velocity and acceleration of the particle when t = 5 s.

[A]. s = 834 mm, v = 1122 mm/s, a = 450 mm/s2
[B]. s = 114 mm, v = 1122 mm/s, a = 450 mm/s2
[C]. s = 114 mm, v = 450 mm/s, a = 1122 mm/s2
[D]. s = 834 mm, v = 450 mm/s, a = 1122 mm/s2

Answer: Option A

Explanation:

No answer description available for this question.

Dheejay said: (Jan 21, 2014)  
How do you get the velocity and acceleration please?

Kumara Swamy said: (May 26, 2018)  
v=ds/dt and a=dv/dt just differentiate.

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