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Engineering Mechanics - Kinematics of Particle (KOP) - Discussion

Discussion Forum : Kinematics of Particle (KOP) - General Questions (Q.No. 18)
Kinematics of Particle (KOP)
18.

A ball thrown vertically upward from the top of a building with an initial velocity of vA = 35 ft/s. Determine (a) how high above the top of the building the ball will go before it stops at B, (b) the time tAB it takes to reach its maximum height, and (c) the total time tAC needed for it to reach the ground at C from the instant it is released.

h = 62.4 ft, tAB = 3.57 s, tAC = 7.14 s
h = 19.02 ft, tAB = 1.087 s, tAC = 2.17 s
h = 19.02 ft, tAB = 1.087 s, tAC = 3.30 s
h = 62.4 ft, tAB = 3.57 s, tAC = 8.56 s
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
1 comments Page 1 of 1.
Rayden said:   3 years ago
Please explain the answer in detail.
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