Engineering Mechanics - General Principles - Discussion
Discussion Forum : General Principles - General Questions (Q.No. 5)
5.
Using the basic trigonomic functions, determine the length of side AB of the right triangle.
Discussion:
12 comments Page 1 of 2.
Vinod Choudhary said:
9 years ago
Sin 30 = AB/AC,
Sin 30 = AB/10 (Because, AC = 10),
1/2 = AB/10 (Because sin 30 = 1/2),
10/2 = AB,
AB = 5 = h.
Sin 30 = AB/10 (Because, AC = 10),
1/2 = AB/10 (Because sin 30 = 1/2),
10/2 = AB,
AB = 5 = h.
Pradeep. said:
1 decade ago
sin30 = ab/ac.
0.5 = ab/10.
So ab = 5.
0.5 = ab/10.
So ab = 5.
Omer Mohammed said:
1 decade ago
AB/sinC = AC/sinB = BC/sinA
sinC = sin30= 0.5
sinB = sin90 = 1
So,
AB/0.5 = 10/1
0.5 AB = 10
AB = 5.
sinC = sin30= 0.5
sinB = sin90 = 1
So,
AB/0.5 = 10/1
0.5 AB = 10
AB = 5.
Karmukilan said:
1 decade ago
Basic Sin (theta) =Opp/Hyp.
So sin30degree=AB/10.
AB=sin30X10.
=0.5X10.
AB=5 this is the ANSWER.
So sin30degree=AB/10.
AB=sin30X10.
=0.5X10.
AB=5 this is the ANSWER.
Koko said:
1 decade ago
sin 30 = 0.5 * ab/bc
opp/adj= 0.5 * 10 = 5
opp/adj= 0.5 * 10 = 5
Akanksha said:
1 decade ago
All explanation are correct.
RookieMathlete said:
1 decade ago
You can easily use sine law, which is (Side A)/(opposite angle) = (Side B)/(opposite angle) = (Side C)/(opposite angle).
in this problem
(Side AB)/Sin30 = 10/Sin90
Side AB = (10(Sin30))/Sin90
AB = 5/sin90
AB = 5
in this problem
(Side AB)/Sin30 = 10/Sin90
Side AB = (10(Sin30))/Sin90
AB = 5/sin90
AB = 5
Nishita said:
1 decade ago
By using 30, 60, 90 degree formula.
We get a ans.
We get a ans.
Shanavaz said:
1 decade ago
sin 30 = 1/2
sin 30 = AB/10
AB = 5
sin 30 = AB/10
AB = 5
Sweety said:
1 decade ago
sin30=AB/10
1/2=AB/10
AB=10/2
AB=5
1/2=AB/10
AB=10/2
AB=5
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