Engineering Mechanics - General Principles - Discussion

Discussion :: General Principles - General Questions (Q.No.5)

5. 


Using the basic trigonomic functions, determine the length of side AB of the right triangle.

[A]. h = 5.77
[B]. h = 11.55
[C]. h = 5
[D]. h = 8.66

Answer: Option C

Explanation:

No answer description available for this question.

Sathiya said: (Dec 13, 2010)  
sin 30 = 0.5
SIN C = OPP / ADJ (c=AB/CA)
CA = 10

So

0.5 =AB/10
AB =10*0.5
AB =5

Suhas said: (Feb 12, 2011)  
Opposite side to the 30 degree in right angle triangle is half of diagonal.

Sweety said: (Feb 12, 2011)  
sin30=AB/10
1/2=AB/10
AB=10/2
AB=5

Shanavaz said: (Mar 1, 2011)  
sin 30 = 1/2
sin 30 = AB/10
AB = 5

Nishita said: (Apr 28, 2011)  
By using 30, 60, 90 degree formula.

We get a ans.

Rookiemathlete said: (Nov 13, 2011)  
You can easily use sine law, which is (Side A)/(opposite angle) = (Side B)/(opposite angle) = (Side C)/(opposite angle).

in this problem
(Side AB)/Sin30 = 10/Sin90
Side AB = (10(Sin30))/Sin90
AB = 5/sin90
AB = 5

Akanksha said: (Nov 30, 2011)  
All explanation are correct.

Koko said: (Feb 20, 2012)  
sin 30 = 0.5 * ab/bc
opp/adj= 0.5 * 10 = 5

Karmukilan said: (Aug 8, 2012)  
Basic Sin (theta) =Opp/Hyp.

So sin30degree=AB/10.

AB=sin30X10.

=0.5X10.

AB=5 this is the ANSWER.

Omer Mohammed said: (Dec 30, 2012)  
AB/sinC = AC/sinB = BC/sinA
sinC = sin30= 0.5
sinB = sin90 = 1

So,

AB/0.5 = 10/1
0.5 AB = 10
AB = 5.

Pradeep. said: (Feb 11, 2015)  
sin30 = ab/ac.
0.5 = ab/10.
So ab = 5.

Vinod Choudhary said: (Sep 10, 2016)  
Sin 30 = AB/AC,

Sin 30 = AB/10 (Because, AC = 10),

1/2 = AB/10 (Because sin 30 = 1/2),

10/2 = AB,

AB = 5 = h.

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