Engineering Mechanics - Force Vectors - Discussion
Discussion Forum : Force Vectors - General Questions (Q.No. 7)
7.
Express the Force F2 in Cartesian vector form.
Discussion:
3 comments Page 1 of 1.
Ahmed said:
1 decade ago
Sir I want explanation for this answer.
Sarah said:
1 decade ago
Component along z axis:
-600 sin 30=-300lb
component along x axis:
(600 cos 30)(cos 45)= 367.42lb
component along y axis:
(600 cos 30)(sin 45)= 367.42lb
answer: {367 i + 367 j - 300k } lb
-600 sin 30=-300lb
component along x axis:
(600 cos 30)(cos 45)= 367.42lb
component along y axis:
(600 cos 30)(sin 45)= 367.42lb
answer: {367 i + 367 j - 300k } lb
Vinay said:
10 years ago
Can anyone explain how is component 600 sin 30 will come?
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