Engineering Mechanics - Force Vectors - Discussion

Discussion :: Force Vectors - General Questions (Q.No.7)

7. 

Express the Force F2 in Cartesian vector form.

[A]. F2 = (155 i + 155 j + 300 k) lb
[B]. F2 = (212 i + 212 j - 519 k) lb
[C]. F2 = (155 i + 155 j - 300 k) lb
[D]. F2 = (367 i + 367 j - 300 k) lb

Answer: Option D

Explanation:

No answer description available for this question.

Ahmed said: (Nov 10, 2011)  
Sir I want explanation for this answer.

Sarah said: (Aug 21, 2012)  
Component along z axis:
-600 sin 30=-300lb
component along x axis:
(600 cos 30)(cos 45)= 367.42lb
component along y axis:
(600 cos 30)(sin 45)= 367.42lb

answer: {367 i + 367 j - 300k } lb

Vinay said: (Jan 26, 2016)  
Can anyone explain how is component 600 sin 30 will come?

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