Electronics - Voltage and Current - Discussion
Discussion Forum : Voltage and Current - General Questions (Q.No. 2)
2.
If 60 J of energy are available for every 15 C of charge, what is the voltage?
Discussion:
162 comments Page 9 of 17.
Ramyasri.Ch said:
1 decade ago
Energy = Charge*Voltage.
In the above question we need to know Voltage So.
Voltage = Energy/Charge.
Energy (Q) = 60Joules.
Charge (C) = 15C.
Therefore Voltage = 60J/15C = 4V.
Thank you friends.
In the above question we need to know Voltage So.
Voltage = Energy/Charge.
Energy (Q) = 60Joules.
Charge (C) = 15C.
Therefore Voltage = 60J/15C = 4V.
Thank you friends.
SANTHIYA.A said:
1 decade ago
P=I^2 R.
I=V/R from ohm law,
Then P=V^2R.
R=V/I.
We get V=P/I.
V=60j/15c.
=4V.
I=V/R from ohm law,
Then P=V^2R.
R=V/I.
We get V=P/I.
V=60j/15c.
=4V.
Venugopal said:
1 decade ago
I=Q/T &........1
P=V*I ,........2
On putting the value of I in equation 2.
P=V*Q/T
E=P*T
E=V*Q/T*T
E=V*Q
V=E/Q
V=60J/15Q
V=4V.
P=V*I ,........2
On putting the value of I in equation 2.
P=V*Q/T
E=P*T
E=V*Q/T*T
E=V*Q
V=E/Q
V=60J/15Q
V=4V.
Sowmiya said:
1 decade ago
Voltage = Energy/Charge.
V = 60/15.
V = 4.
V = 60/15.
V = 4.
Xyz said:
1 decade ago
P=W/t
Therefore W=P*t
And P=V*I
So W=V*I*t
Now q=I*t
Therefore W=V*q
So V=W/q=60/15=4V
Therefore W=P*t
And P=V*I
So W=V*I*t
Now q=I*t
Therefore W=V*q
So V=W/q=60/15=4V
Prashant said:
1 decade ago
Voltage is the electric potential energy per unit charge.
V = E/Q
V = 60/14
V = 4 volt
V = E/Q
V = 60/14
V = 4 volt
Peeyush said:
1 decade ago
W = QV, SO V = W/Q, THEN V = 60/15, V = 4VOLT
Rubiya said:
1 decade ago
E=1/2*c*v^2 from this V=8v then which formula apply for this question?
Naresh said:
1 decade ago
One of my friend written 1/2*c*v*v formula and he got 8j as the answer,
Here c is capacitance, but in question c is charge so we have to apply voltage= (energy/charge).
Here c is capacitance, but in question c is charge so we have to apply voltage= (energy/charge).
Dinesh said:
1 decade ago
Q=C*V,60=15*v,V=4 v
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