Electronics - Voltage and Current - Discussion
Discussion Forum : Voltage and Current - General Questions (Q.No. 2)
2.
If 60 J of energy are available for every 15 C of charge, what is the voltage?
Discussion:
162 comments Page 8 of 17.
MORIES MANOHAR said:
1 decade ago
Energy = Voltage * Current
60 = Voltage*15
Voltage = 60/15
Voltage = 4
60 = Voltage*15
Voltage = 60/15
Voltage = 4
Parag said:
1 decade ago
V=Q/C=60/15=4v
Q=ENERGY in joules=60
C=Charge in coulombs=15
joules/coulomb is voltage
Q=ENERGY in joules=60
C=Charge in coulombs=15
joules/coulomb is voltage
Priyank said:
1 decade ago
Energy =Charge*voltage
=>voltage=energy/charge
=>V=60/15=4
Hence 4V is the answer
=>voltage=energy/charge
=>V=60/15=4
Hence 4V is the answer
Jayapriya said:
1 decade ago
We know that c=q/v
So v=q/c
=60/15
=4v
So v=q/c
=60/15
=4v
Kumaraguru said:
1 decade ago
Q = C*V
Q --> Energy
C --> Charge
V --> Voltage
V = Q / C
= 60/15 = 4 Voltage
Q --> Energy
C --> Charge
V --> Voltage
V = Q / C
= 60/15 = 4 Voltage
Tayyaba said:
1 decade ago
Voltage = work done on unit charge.
V=W/Q or V=E/Q.
V=60/15.
V=4v.
V=W/Q or V=E/Q.
V=60/15.
V=4v.
Sasikumar said:
1 decade ago
Given energy=60j.
Charge=15c.
We know that Q=CV=>V=Q/C=60/15=4v.
Charge=15c.
We know that Q=CV=>V=Q/C=60/15=4v.
DHANRAJ said:
1 decade ago
V = E/C V:VOLTAGE, C:COLOUMN and E:ENERGY.
= 60/15 .
= 4 .
= 60/15 .
= 4 .
Ningu said:
1 decade ago
V = Energy/Charge.
V = 60/15.
V = 4.
V = 60/15.
V = 4.
Ramyasri.Ch said:
1 decade ago
Chetan Kumar and Jaimin Patel Gujarat you both are wrong why because
you said that Energy=1/2CV^2
It's Correct for Electrical Energy stored in a Capacitor Only.
Then
U=QV/2=CV^2/2
Where U=Potential Energy
Q=Coulombs(C)
V=Volts(V)
C=Capacitance in frads.
But In the above problem we should use the formula that
Energy(Q)=Charge(C)*Voltage(V)
Q=CV
V=Q/C; Where V stands for Voltage
Thanks to all of you and especially for Vinod who told that Chetan was wrong.If we know the correct answer then only we can say that to anyone But to say it's wrong we should have guts that type of daring i got from Vinod.Thank you Vinod.
you said that Energy=1/2CV^2
It's Correct for Electrical Energy stored in a Capacitor Only.
Then
U=QV/2=CV^2/2
Where U=Potential Energy
Q=Coulombs(C)
V=Volts(V)
C=Capacitance in frads.
But In the above problem we should use the formula that
Energy(Q)=Charge(C)*Voltage(V)
Q=CV
V=Q/C; Where V stands for Voltage
Thanks to all of you and especially for Vinod who told that Chetan was wrong.If we know the correct answer then only we can say that to anyone But to say it's wrong we should have guts that type of daring i got from Vinod.Thank you Vinod.
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