### Discussion :: Voltage and Current - General Questions (Q.No.2)

Gowri Shankar said: (Oct 14, 2010) | |

Voltage = energy/charge = 60/15 = 4. |

Dhivya said: (Oct 14, 2010) | |

Energy = Charge * Voltage. Voltage = Energy / Charge. |

Ravikumar said: (Oct 15, 2010) | |

Volt* Coulombs/sec = Joules/sec. Volt = Joules/Coulombs = 60/15 = 4v. |

M.Naresh said: (Oct 19, 2010) | |

E = 1/2*C*(V)^2 where E = Energy, C = Capicitanence, V = Voltage |

Sekar said: (Oct 22, 2010) | |

Energy = Voltage * Current 60 = Voltage*15 Voltage = 60/15 Voltage = 4 |

.M.Pandiyarajan said: (Oct 22, 2010) | |

a] energy in power=60 b] current in charge=15 Formula : p=v*i v=p/i v=60/15 v=4v |

Chetan Kumar said: (Oct 26, 2010) | |

ENERGY=(1/2)C*V*V SO ENERGY=1/2Q*V V=2*60/15 V=8 volt ???????????????? |

Vinay said: (Nov 22, 2010) | |

current=charge/time power=voltage*current p=qv/t E=p*t=q*v v=E/q=60/15=4 volts |

Manjula said: (Dec 6, 2010) | |

E=qv v=q/E V=60/15=4V |

Shekhar said: (Dec 15, 2010) | |

Here problem is about a single charge . if suppose +Ve charge has 15C charge and has energy 60 J than what is the value of potential generated by it. we can not treat it as capacitor because in capacitor we treat the potential difference applied between plates.so kindly have it simple case. E = q . V = = 4 volt |

T. Lakshmi said: (Dec 21, 2010) | |

w=60J q=15C v= w/q v=60/15 v=4v |

Srinaga said: (Dec 26, 2010) | |

Hey Here problem is about a single charge . if suppose +Ve charge has 15C charge and has energy 60 J than what is the value of potential generated by it. we can not treat it as capacitor because in capacitor we treat the potential difference applied between plates.so kindly have it simple case. E = q . V = = 4 volt |

Shakeer said: (Dec 27, 2010) | |

Thanks to all. |

Kinjal Patel said: (Dec 29, 2010) | |

energy = charge 8 columb = 60 j/15 c = 4 v |

Swapnil said: (Dec 31, 2010) | |

Let V=voltage to be found, I=current passing through the circuit in time 't' & Q=charge in coulombs. Then, electrical power P & current I are given by P=V*I.....(1) & I=dQ/dt...(2) so, the electrical energy E is E=V*Q.....(3) Since E=60 J(Given) & Q=15 C(Given), V=E/Q=(60/15) V =4 V |

Bharatesh said: (Jan 3, 2011) | |

E=Q*V V=Q/V =60/15 =4v |

Yogeshwari Mahanti said: (Jan 6, 2011) | |

Charge= Energy/voltage Q = E/V 60 = 15/V V = 4V |

Universal said: (Jan 9, 2011) | |

1 Joule = 1coulomb * 1voltage |

Coolfunnyguy said: (Jan 14, 2011) | |

E=(1/2)*C*[(V)^2] v^2=(2*E)/C ==>v^2=2*60/15 v^2=8 V=~4V |

Sahana949 said: (Jan 17, 2011) | |

It is easier to understand if you say the charge flows during a time t, then the current is 15/t Amps. The power available is 60/t Watts. Watts = Volts * Amps 60/t = V * 15/t V = 4 |

Vinod Kr Yadav said: (Jan 24, 2011) | |

Chetan kumar you are not right. Thanks to all of you. |

Syed Asif said: (Jan 29, 2011) | |

Energy and work done are same. We khow that v=w/q. Therefore 60/15=4. |

Prasant said: (Feb 6, 2011) | |

e=v*i*t q=i*t e=v*q v=e/q q is charge i is current e is energy v is voltage generated t is time of charge flow |

G.Sreelakshmi said: (Feb 16, 2011) | |

We know that charge Q=E/V v=e/q v=60/15 v=4v |

Ramesh Nirjogi said: (Apr 15, 2011) | |

v=w/q v=60/15 v=4v or p=vi p=v(q/t) e=pt=vq |

Chetaya said: (Apr 20, 2011) | |

energy=charge*voltage hence voltage=energy/charge voltage=60/15=4volt. |

Devaki said: (Apr 28, 2011) | |

Energy = charge * voltage here Voltage =? voltage = Energy / charge = 60 / 15 = 4 Hence voltage = 4V |

Sireesha said: (May 8, 2011) | |

power=energy/time power=voltage*current so v*i/t =energy charge=i*t given charge=15c v*15=60 voltage is 4v. |

Sunitha said: (May 9, 2011) | |

Here voltage=? Voltage=energy/charge. Hence v=60/15=4v. |

Arnold Anand said: (May 10, 2011) | |

We know the current i=15 energy is 60 j, hav to find the voltage? v=energy/current =60/15 =4V |

Naveen said: (May 24, 2011) | |

v=w/q Therefore v=60/15= 4v. |

Vijay said: (May 28, 2011) | |

i be the charge(15c)/time and p be the power 60j/watt so p= vi |

Krishna said: (May 29, 2011) | |

q=c*v q is charge,v is voltage,c is capacitence 60=15*v Hence v=4volt |

Shashi said: (Jun 1, 2011) | |

charge=15 voltage=? energy=60 so voltage=energy/charge i.e.60/15= 4volt. |

Ramraj said: (Jun 4, 2011) | |

Voltage= no of joules / coulomb. 60/15=4v. |

Anju said: (Jun 6, 2011) | |

E=QV V=E/Q V=60/15 V=4 Where, E=energy measured in joules Q=charge measured in coulomb v=voltage measured in volt |

Udayan Kamble said: (Jul 4, 2011) | |

VOLTS x COULOMBS = JOULES ANSWER = 60/15 = 4 It takes energy to push some charge against the voltage pressure Whenever a certain amount of charge is pushed through an electrical resistance, some electrical energy is lost from the circuit and heat is created. A certain amount of energy flows into the "frictional" resistor every second, and a certain amount of heat energy flows back out again. If we increase the voltage, then for the same hunk of charge being pushed through, more energy flows into the resistor and gets converted to heat. If we increase the hunk of charge, same thing: more heat flows out per second. Here's how to write this: |

Purnesh Nerale said: (Jul 12, 2011) | |

Thanks Friends. |

Raghu said: (Jul 23, 2011) | |

Q=CV SO,V=Q/C *V=60/15 *V=4v |

Girish Bhat M said: (Aug 7, 2011) | |

P=VI => W/T=V(Q/T) => w=VQ => 60=V(15) =. V=4v |

Preeth said: (Aug 8, 2011) | |

I feel vinay is right. |

Ruchi Mishra said: (Aug 10, 2011) | |

I=Q/T &........1 P=V*I ,........2 On putting the value of I in equation 2. P=V*Q/T E=P*T E=V*Q/T*T E=V*Q V=E/Q V=60J/15Q V=4V. |

Brijesh Rathod said: (Aug 20, 2011) | |

E=QV V=E/Q V=60/15 V=4 Where:- E=energy measured in joules. Q=charge measured in coulomb. v=voltage measured in volt. |

Arun Jain said: (Aug 25, 2011) | |

E = 1/2 * C * V^2 With the help of this Einsten Eq. the Ans. Should be 8V. but this is not a option, so we can go through to this way I= Q/T &........1 P=V*I ,........2 On putting the value of I in equation 2. P=V*Q/T E=P*T E=V*Q/T*T E=V*Q V=E/Q V=60J/15Q V=4V. |

Mahesh said: (Aug 27, 2011) | |

Voltage is defined as the energy per unit charge. |

Sarath Kumar said: (Sep 25, 2011) | |

v = voltage; e = energy in joules = 60 Q = charge in couloumbs = 15 v = e/q => 60/15 *v = 4; |

Bhargav said: (Nov 19, 2011) | |

Joules are volt-coulombs; that is, when you put one coulomb of electrons through a potential difference of 1 volt, you do one joule of work on the system. So you find the number of joules of work (or energy put in to the system) by multiplying the number of coulombs by the number of volts. |

Anju said: (Nov 23, 2011) | |

The potential difference or voltage, V across two points is defined as energy, E dissipated or transferred by coulomb of charge, Q that moves through the two points. Therefore: Potential difference = Electrical energy dissipated Charge V= E /Q V= Voltage E= Energy Q= Charge |

Boopathi said: (Dec 13, 2011) | |

E=energy measured in joules. Q=charge measured in coulomb. v=voltage measured in volt. V=60/15 V=4 volt |

Abhinai said: (Dec 14, 2011) | |

V=SQRT OF(2*E/C) |

Sridevi said: (Dec 15, 2011) | |

JOULES=VOLT*COULOMB 60=V*15 V=60/15 V=4 |

Swarna Jha said: (Jan 23, 2012) | |

As per jouleS formula VOLTAGE=ENERGY/CHARGE SUPPLIED. V=60/15=4V. |

Sourabh Sahu said: (Jan 24, 2012) | |

Apply energy is equals to hunkout charge and apply vootage. So e=qV. |

Ashsih said: (Jan 28, 2012) | |

Electrical Energy = KWHr Power = Voltage * Current - (i) i=(q/t) hence Charge (q) = i * t Thus E = Power * t E = V * i * t E = V * q V = E / q v = 60/15 V = 4v |

Atul Mehta,Wit said: (Feb 4, 2012) | |

The option 'a' is correct because we know that power=volt*current. power is measured in joule. while current is flow of charges having unit coulomb. v=p/c =60/15=4 |

Sadanandam said: (Feb 9, 2012) | |

V=W/Q; GENERAL FORMULA; I.E V=? W=P=E=60; Q=15; 60/15=4;//ANS |

Avinash.A said: (Mar 1, 2012) | |

The definition of potential or voltage is workdone in moving a charge from one point to another. So 1V is defined as 1J of energy spent in moving 1C of charge so here 60J of energy is demanding in moving 15C of charge so potential is 4V. |

Amit Singh said: (Mar 2, 2012) | |

V=W/Q; GENERAL FORMULA; I.E V=? W=P=E=60; Q=15; 60/15=4;//ANS |

D.Saibabu said: (Mar 7, 2012) | |

Here he has given that Energy=60j and q charge =15c We know that potential(v) is nothing but the energy per unit charge so V=E/q V=60/15 V=4v |

Jaimin Patel Gujarat said: (Mar 8, 2012) | |

1/2*(c*v*v)=u(energy) |

Bheemreddy said: (Mar 10, 2012) | |

Q = CV So V = Q/C. |

Dinabandhu Sabata said: (Mar 10, 2012) | |

Energy=Power*t E=V*I*t E=V*Q V=E/Q V=60/15=4V |

Seetharaman said: (Apr 13, 2012) | |

V=IR P=VI V= E /Q V= Voltage E= Energy Q= Charge Time V=60/15=4V |

Mories Manohar said: (Apr 18, 2012) | |

Energy = Voltage * Current 60 = Voltage*15 Voltage = 60/15 Voltage = 4 |

Parag said: (Apr 19, 2012) | |

V=Q/C=60/15=4v Q=ENERGY in joules=60 C=Charge in coulombs=15 joules/coulomb is voltage |

Priyank said: (Apr 22, 2012) | |

Energy =Charge*voltage =>voltage=energy/charge =>V=60/15=4 Hence 4V is the answer |

Jayapriya said: (May 9, 2012) | |

We know that c=q/v So v=q/c =60/15 =4v |

Kumaraguru said: (May 27, 2012) | |

Q = C*V Q --> Energy C --> Charge V --> Voltage V = Q / C = 60/15 = 4 Voltage |

Tayyaba said: (Jun 3, 2012) | |

Voltage = work done on unit charge. V=W/Q or V=E/Q. V=60/15. V=4v. |

Sasikumar said: (Jun 4, 2012) | |

Given energy=60j. Charge=15c. We know that Q=CV=>V=Q/C=60/15=4v. |

Dhanraj said: (Jun 20, 2012) | |

V = E/C V:VOLTAGE, C:COLOUMN and E:ENERGY. = 60/15 . = 4 . |

Ningu said: (Jun 23, 2012) | |

V = Energy/Charge. V = 60/15. V = 4. |

Ramyasri.Ch said: (Jun 28, 2012) | |

Energy = Charge*Voltage. In the above question we need to know Voltage So. Voltage = Energy/Charge. Energy (Q) = 60Joules. Charge (C) = 15C. Therefore Voltage = 60J/15C = 4V. Thank you friends. |

Ramyasri.Ch said: (Jun 28, 2012) | |

Chetan Kumar and Jaimin Patel Gujarat you both are wrong why because you said that Energy=1/2CV^2 It's Correct for Electrical Energy stored in a Capacitor Only. Then U=QV/2=CV^2/2 Where U=Potential Energy Q=Coulombs(C) V=Volts(V) C=Capacitance in frads. But In the above problem we should use the formula that Energy(Q)=Charge(C)*Voltage(V) Q=CV V=Q/C; Where V stands for Voltage Thanks to all of you and especially for Vinod who told that Chetan was wrong.If we know the correct answer then only we can say that to anyone But to say it's wrong we should have guts that type of daring i got from Vinod.Thank you Vinod. |

Santhiya.A said: (Jun 28, 2012) | |

P=I^2 R. I=V/R from ohm law, Then P=V^2R. R=V/I. We get V=P/I. V=60j/15c. =4V. |

Venugopal said: (Jul 24, 2012) | |

I=Q/T &........1 P=V*I ,........2 On putting the value of I in equation 2. P=V*Q/T E=P*T E=V*Q/T*T E=V*Q V=E/Q V=60J/15Q V=4V. |

Sowmiya said: (Jul 30, 2012) | |

Voltage = Energy/Charge. V = 60/15. V = 4. |

Xyz said: (Aug 2, 2012) | |

P=W/t Therefore W=P*t And P=V*I So W=V*I*t Now q=I*t Therefore W=V*q So V=W/q=60/15=4V |

Prashant said: (Aug 18, 2012) | |

Voltage is the electric potential energy per unit charge. V = E/Q V = 60/14 V = 4 volt |

Peeyush said: (Aug 29, 2012) | |

W = QV, SO V = W/Q, THEN V = 60/15, V = 4VOLT |

Rubiya said: (Sep 6, 2012) | |

E=1/2*c*v^2 from this V=8v then which formula apply for this question? |

Naresh said: (Sep 11, 2012) | |

One of my friend written 1/2*c*v*v formula and he got 8j as the answer, Here c is capacitance, but in question c is charge so we have to apply voltage= (energy/charge). |

Dinesh said: (Sep 16, 2012) | |

Q=C*V,60=15*v,V=4 v |

Vinayagamoorthi said: (Oct 3, 2012) | |

Voltage = Energy/degree =60/15 =4 |

Sohaib Shekh said: (Oct 13, 2012) | |

V=I*R V=60*15 V=900 |

Krishna Kumar Goswami said: (Oct 19, 2012) | |

As we all know power= voltage*current, And Power= work/time , current= charge/time So, Work= voltage*charge NOW 60= VOLTAGE*15 SO, VOLTAGE= (60/15)= 4V. |

Nandajit said: (Nov 1, 2012) | |

60J means 60 watt in 1 sec. In 1 sec current is I=Q/t=15/1(Q is charge and t is time)=15 amps. Again Watt=Voltage*Current Therefore,60=V*15(V is voltage) V=4V |

M.Dineshkumar, Me(Embedded Systems) said: (Dec 29, 2012) | |

Voltage=Energy/unit charge. E=60J, q=15C. V=joule/coulomb. V=60/15=4V. |

Suren said: (Jan 11, 2013) | |

I agree that energy is the multiplication of voltage and charge. |

Dilshad Chauham said: (Mar 11, 2013) | |

Given data E=60 j , Q = 15. we know that Energy = charge*voltage. Then, Voltage = Energy/charge. Voltage = 60/15. V = 4v. |

Aravind said: (Mar 27, 2013) | |

Voltage is workdone in moving 15C of charge hence 60/15=4V. |

Balaji said: (Apr 4, 2013) | |

Voltage is work done in moving 15C of charge. Hence v = energy/charge = 60/15 = 4v. |

Kanzariya Vijay said: (Jul 19, 2013) | |

E = Q*V. (ENERGY=charge*voltage). V = Q/E. (voltage=ENERGY/charge). Q = 60, E = 15. V = 60/15. V = 4. |

Deepak Arya said: (Aug 3, 2013) | |

It is easier to understand if you say the charge flows during a time t, then the current is 15/t Amps. The power available is 60/t Watts. Watts = Volts * Amps. 60/t = V * 15/t. V = 4. |

Sachidananda Swain said: (Aug 4, 2013) | |

Let V=voltage to be found, I=current passing through the circuit in time 't' & Q=charge in coulombs. Then, electrical power P & current I are given by, P = V*I.....(1). & I = dQ/dt...(2). So, the electrical energy E is: E = V*Q.....(3). Since E = 60 J(Given) & Q = 15 C(Given), V = E/Q = (60/15). V = 4 V. |

Aditya said: (Aug 4, 2013) | |

E = eV. e = 15 C. E = 60. There 4V = E/e = 60/15 = 4. |

Vamsikrishna said: (Aug 20, 2013) | |

Energy stored by the capacitor in the form of charge. Given by Energy (Q) = Charge (c) X Voltage (v). 60= 15 X Voltage. Voltage = 60/15 = 4v. |

Pradeep Kushwaha said: (Sep 3, 2013) | |

p=power=60 c=current=15 findout=v we know that p=v*i so v=p/i v=60/15=4v |

Lakshmi Byreddy said: (Sep 25, 2013) | |

E=qV. Where E=60J and q=15c. Then V=4V. |

Sibly Sadik said: (Oct 6, 2013) | |

We know that, energy = voltage*charge. So charge = energy/voltage. Let, V = 60/15 = 4v. Answer: 4v. |

Kumudini said: (Nov 30, 2013) | |

We know Q = CV. V = Q/C. V= 60/15 = 4V. |

Prerna Agrawal said: (Dec 10, 2013) | |

An ideal capacitor is wholly characterized by a constant capacitance C, defined as the ratio of charge Q on each conductor to the voltage V between them c = q/v. So rearrange above equation, v = q/c. v = 60/15. v = 4v. |

Vijay Soni said: (Feb 5, 2014) | |

The problem is for only one charge, hence capacitor fundamental can't be applied, therefore simple energy relation can be used here i.e. E = q*v. => v = E/q. v = 60/15. v = 4V. |

Arun said: (Feb 23, 2014) | |

Q = 15c, and E = 60j given, P = V*I. dE/dt = P = V*I. I = dQ/dt. E = V*Q. V = E/Q = 60/15 = 4. |

Vijaykumar said: (Mar 1, 2014) | |

Condition 1: Energy = Charge * Voltage. Then, Voltage = Energy by Charge. |

Shahid said: (Mar 18, 2014) | |

Voltage is equal to work per unit charge. V = w/q. V = 60/15 = 4. |

Saru said: (Apr 7, 2014) | |

The potential energy is a form of energy and the potential (and therefore voltage, when differences are taken) is defined as the potential energy (or potential energy difference) per unit charge, V=E/Q. V = 60/15 = 4. |

Radhika said: (Jul 2, 2014) | |

E = Q*V. 60 = 15*V. V = 60/15. V = 4V. |

Hitesh Virani said: (Jul 29, 2014) | |

60/15 = 4 Volts. It is easier to understand if you say the charge flows during a time t, then the current is 15/t Amps. The power available is 60/t Watts. Watts = Volts * Amps 60/t = V * 15/t. V = 4. |

Bhagyashri Kale said: (Aug 31, 2014) | |

V = voltage. E = energy. C = charge. As we know that E=C*V. V = E/c. V = 60/15. V = 4. |

Komal Sharma said: (Oct 5, 2014) | |

V = ENERGY/CHARGE. V = 16/15. V = 4. |

Yogesh Mahajan said: (Nov 2, 2014) | |

To find voltage. Given Energy = 60j. Charge = 15. By formula V = E/C = 60/15 = 4. |

Joshi Girish V. said: (Dec 16, 2014) | |

The Unit For The Measurement Of Charge Is Coulomb Which is Equal To 6.28*10^18 Electrons/Second. The Unit For The Measurement Of Current Is Ampere Which Is Equal To 1 Coulomb/Second. Therefore, Current = 15C/Second. Electrical Energy = Power*Time = 60J (KWH). Power = Current*Voltage. Therefore, Electrical Energy = Current*Voltage*Time. Therefore, 60J = 15C*Voltage*1 Second. Therefore, Voltage = 60J/15C*1. Therefore, Voltage = 4V*1. Therefore, Voltage = 4V. |

Chinnappar.E said: (Mar 5, 2015) | |

Voltage = Power/Charge. So, v = 60/15 = 4 v. |

Muji said: (Mar 26, 2015) | |

Voltage = (Work done/Charge). Energy is ability to do work. So, Voltage = (w/q). = (E/q). = 60/15. = 4 volt. |

Mohan said: (Mar 29, 2015) | |

Energy = 1/2(CV^2). C = Charge. V = Voltage. V^2 = 2E/C. V^2 = (40/3). V = 3.6. V = 4. |

Dattatreya said: (Jun 29, 2015) | |

E = q*v. 60 = 15.v. v = 60/15 = 4V. |

Aman said: (Jul 4, 2015) | |

Energy = qV. Since electric field strength is E = F/q = V/d. With V = voltage, d = distance between charged plates. Fd = qV. Energy = qv. |

Sonu Kumar said: (Jul 7, 2015) | |

Energy = C*V. 60 = 15*V. V = 60/15. V = 4. |

Pradeep said: (Jul 8, 2015) | |

I think your relation give the above problem right. |

Rafique Ansari said: (Aug 6, 2015) | |

V = J/C. = 60/15. = 4. |

Kumar Shanu said: (Sep 8, 2015) | |

Since Q = CV given that Q = 60 and C = 15. So answer is V = Q/C = 60/15 = 4v. |

Milind Zuge said: (Sep 10, 2015) | |

Energy = Charge/Voltage. = 60/15 = 4. |

R.V.Ramana said: (Sep 21, 2015) | |

Energy = Voltage*Charge (Current). 60 = Voltage*15. 60/15 = Voltage. 4 = Voltage. |

Summi said: (Dec 7, 2015) | |

V = E/Q. V = 60/15. V = 4. |

Nasrullah Khan said: (Jan 13, 2016) | |

E = V*Q. E = 60 J. Q = 15 C. V = E/Q means 60/15 = 4 V. |

Asrori said: (Jan 18, 2016) | |

Seriously mate? E = CV? E = 0.5CV^2 is the formula. V should be 2*2 volts. |

Sandeep said: (Mar 5, 2016) | |

V = J/C = 60J/15C = 4V. |

Vani said: (Mar 24, 2016) | |

V = J/C. V = 60J/15C. V = 4V. |

Bala said: (Apr 9, 2016) | |

v = J/c. v = 60J. c = 15c. v = 4v. |

Pavithira said: (Apr 15, 2016) | |

c = q/v. v = q/c. = 60/15. = 4. |

Agba Samuel said: (May 29, 2016) | |

E = qv, where E = energy, q = quantity of charge, v = voltage. Make v the subject of the formular v = E/q. So, v = 60/15 = 4v --> Ans. |

Sonali K said: (Jul 9, 2016) | |

Watts = Volts * Amps, 60/t = V * 15/t, V = 4. |

Rajeshkumar said: (Aug 17, 2016) | |

60/15 = 4 simple. |

Brijesh Kumar Vishwakarma said: (Aug 19, 2016) | |

60/15 = 4v. |

Yuvaraj said: (Aug 24, 2016) | |

60/15 = 4 volt. |

Sandeep said: (Sep 12, 2016) | |

It is easier to understand if you say the charge flows during a time t, then the current is 15/t Amps. The power available is 60/t Watts. Watts = Volts * Amps. 60/t = V * 15/t. V = 4. |

Atul Kushwaha said: (Oct 29, 2016) | |

V = q/c. So 60/15 = 4ans. |

Gunwant said: (Jan 22, 2017) | |

E = I^2R E = I * IR E = I * V. (V=E/I ) Joules=Coloumb * Volts. (Volts=Joules/ Coloumb). Here, 60 = 15 * Volts. Volts = 60/15, Volts = 4. |

Mitali Bawankule said: (Jan 28, 2017) | |

The answer is 4. By the formula voltage = energy/charge. Voltage = 60/15 = 4. |

Jeevan Thakare said: (Feb 4, 2017) | |

Power = volt * current. Current is the amount of charge flowing through a cross section of the conductor in unit time here 't'. So, current =15/t and the power is energy dissipates in time t so here 60/t. 60/t = volt*15/t. volt = 4 volt. |

Nemai said: (Feb 18, 2017) | |

Energy= Volt x Current x Time. Charge = Current (const) x Time. So, according to question V= 60 / 15 = 4 V. |

Mahesh Yadav said: (Feb 24, 2017) | |

E=Q * V. 60J = 15Q * V, V = 60J ÷15Q, V = 4V. |

Deepak Bammidi said: (Apr 1, 2017) | |

Simply, energy is equal to product of charge and voltage. So the answer is 4v. |

Kritika said: (May 27, 2017) | |

E=q * v. V=E÷q. V =60÷15, V=4 volt. |

Atul Kushwaha said: (Aug 25, 2017) | |

Energy=voltage*charge so voltage=energy/charge. Where, energy=60, charge=15 voltage= ? 60/15= 4answer. |

Salim said: (Sep 13, 2017) | |

Here, E=V*Q. |

Sushil said: (Sep 23, 2017) | |

Q=60J C=15C V=? we have, Q=c*v or,60=15*v or,v=60/15 So,v=4V. |

Linnthant said: (Nov 4, 2017) | |

W = Vq. V = W/q. So, V = 60/15 = 4V. |

Hemanth said: (Dec 16, 2017) | |

Energy =voltage *charge. Therefore, Voltage=energy/charge. Voltage=60J/75c. =4v. |

Durgesh Shukla said: (Apr 1, 2018) | |

W=V*Q. V=W÷Q. So, V= 60÷15, V=4 volt. |

Siyosi said: (Apr 25, 2018) | |

E=q.v. In electronics engineering this is a formula of very small energy, which is also known as " electron volt " we can say that charge*voltage is equals to Energy. |

Rafi said: (Aug 25, 2018) | |

E = Pt. P = VI=V*(Q/t)=VQ/t; E = (VQ/t)*t=VQ; E = VQ, 60 = V*15, V = 4v. |

Rafi said: (Aug 25, 2018) | |

Here we should not take energy as magnetic or capacitive since it is not mentioned. E=Pt and P=VI=V* (Q/t). =>E=V*Q. =>V=4---->answer. |

Jignesh Bhandari said: (Mar 30, 2019) | |

V = W/Q, V = 60/15, V = 4. |

Hmj said: (Apr 24, 2019) | |

Q = C * V. V = Q/C. 4 = 60/15. |

Hmj said: (Apr 24, 2019) | |

Q/C = V. 60/15 = 4. |

Ranjitha said: (May 29, 2019) | |

E = qV. V = E/q, V = 60J/15C, V = 4V. E -> Energy. q -> charge. v -> voltage or potential difference. |

Narendran A I said: (Jul 9, 2019) | |

Joule is energy gained by 1 coulomb of charge when placed in a potential difference of 1 volt. Hence, Joule = Coulomb times Volt. Given, Energy =60 J, Charge = 15 C therefore Voltage =(60/15) = 4 Volts. |

Santosh Kumar said: (Aug 25, 2019) | |

We know that: V= w/Q. Written as this formula; V=j/c. = j= 60, =C= 15, = 15/60, V=4 = Answer. |

#### Post your comments here:

Name *:

Email : (optional)

» Your comments will be displayed only after manual approval.