Electronics - Voltage and Current - Discussion
Discussion Forum : Voltage and Current - General Questions (Q.No. 2)
2.
If 60 J of energy are available for every 15 C of charge, what is the voltage?
Discussion:
162 comments Page 4 of 17.
G.sreelakshmi said:
1 decade ago
We know that charge Q=E/V
v=e/q
v=60/15
v=4v
v=e/q
v=60/15
v=4v
Ramesh nirjogi said:
1 decade ago
v=w/q
v=60/15
v=4v
or
p=vi
p=v(q/t)
e=pt=vq
v=60/15
v=4v
or
p=vi
p=v(q/t)
e=pt=vq
Chetaya said:
1 decade ago
energy=charge*voltage
hence voltage=energy/charge
voltage=60/15=4volt.
hence voltage=energy/charge
voltage=60/15=4volt.
Devaki said:
1 decade ago
Energy = charge * voltage
here Voltage =?
voltage = Energy / charge
= 60 / 15 = 4
Hence voltage = 4V
here Voltage =?
voltage = Energy / charge
= 60 / 15 = 4
Hence voltage = 4V
Sireesha said:
1 decade ago
power=energy/time
power=voltage*current
so v*i/t =energy
charge=i*t
given charge=15c
v*15=60
voltage is 4v.
power=voltage*current
so v*i/t =energy
charge=i*t
given charge=15c
v*15=60
voltage is 4v.
Sunitha said:
1 decade ago
Here voltage=?
Voltage=energy/charge.
Hence v=60/15=4v.
Voltage=energy/charge.
Hence v=60/15=4v.
Arnold anand said:
1 decade ago
We know the current i=15
energy is 60 j,
hav to find the voltage?
v=energy/current
=60/15
=4V
energy is 60 j,
hav to find the voltage?
v=energy/current
=60/15
=4V
Naveen said:
1 decade ago
v=w/q
Therefore v=60/15= 4v.
Therefore v=60/15= 4v.
Vijay said:
1 decade ago
i be the charge(15c)/time and p be the power 60j/watt so
p= vi
p= vi
Krishna said:
1 decade ago
q=c*v
q is charge,v is voltage,c is capacitence
60=15*v
Hence v=4volt
q is charge,v is voltage,c is capacitence
60=15*v
Hence v=4volt
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