Electronics - Voltage and Current - Discussion
Discussion Forum : Voltage and Current - General Questions (Q.No. 2)
2.
If 60 J of energy are available for every 15 C of charge, what is the voltage?
Discussion:
162 comments Page 3 of 17.
Kinjal patel said:
1 decade ago
energy = charge 8 columb
= 60 j/15 c
= 4 v
= 60 j/15 c
= 4 v
Swapnil said:
1 decade ago
Let V=voltage to be found, I=current passing through the circuit in time 't' & Q=charge in coulombs. Then, electrical power P & current I are given by
P=V*I.....(1)
&
I=dQ/dt...(2)
so, the electrical energy E is
E=V*Q.....(3)
Since E=60 J(Given) & Q=15 C(Given),
V=E/Q=(60/15) V =4 V
P=V*I.....(1)
&
I=dQ/dt...(2)
so, the electrical energy E is
E=V*Q.....(3)
Since E=60 J(Given) & Q=15 C(Given),
V=E/Q=(60/15) V =4 V
Bharatesh said:
1 decade ago
E=Q*V
V=Q/V
=60/15
=4v
V=Q/V
=60/15
=4v
YOGESHWARI MAHANTI said:
1 decade ago
Charge= Energy/voltage
Q = E/V
60 = 15/V
V = 4V
Q = E/V
60 = 15/V
V = 4V
Universal said:
1 decade ago
1 Joule = 1coulomb * 1voltage
Coolfunnyguy said:
1 decade ago
E=(1/2)*C*[(V)^2]
v^2=(2*E)/C ==>v^2=2*60/15
v^2=8
V=~4V
v^2=(2*E)/C ==>v^2=2*60/15
v^2=8
V=~4V
Sahana949 said:
1 decade ago
It is easier to understand if you say the charge flows during a time t, then the current is 15/t Amps. The power available is 60/t Watts. Watts = Volts * Amps
60/t = V * 15/t
V = 4
60/t = V * 15/t
V = 4
Vinod kr yadav said:
1 decade ago
Chetan kumar you are not right. Thanks to all of you.
Syed asif said:
1 decade ago
Energy and work done are same.
We khow that v=w/q.
Therefore 60/15=4.
We khow that v=w/q.
Therefore 60/15=4.
Prasant said:
1 decade ago
e=v*i*t
q=i*t
e=v*q
v=e/q
q is charge
i is current
e is energy
v is voltage generated
t is time of charge flow
q=i*t
e=v*q
v=e/q
q is charge
i is current
e is energy
v is voltage generated
t is time of charge flow
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