Electronics - Voltage and Current - Discussion

I=Q/T &........1
P=V*I ,........2
On putting the value of I in equation 2.
P=V*Q/T
E=P*T
E=V*Q/T*T
E=V*Q
V=E/Q
V=60J/15Q
V=4V.

I feel vinay is right.

P=VI
=> W/T=V(Q/T)
=> w=VQ
=> 60=V(15)
=. V=4v

Q=CV
SO,V=Q/C
*V=60/15
*V=4v

Thanks Friends.

VOLTS x COULOMBS = JOULES
ANSWER = 60/15 = 4
It takes energy to push some charge against the voltage pressure

Whenever a certain amount of charge is pushed through an electrical resistance, some electrical energy is lost from the circuit and heat is created. A certain amount of energy flows into the "frictional" resistor every second, and a certain amount of heat energy flows back out again. If we increase the voltage, then for the same hunk of charge being pushed through, more energy flows into the resistor and gets converted to heat. If we increase the hunk of charge, same thing: more heat flows out per second. Here's how to write this:

E=QV
V=E/Q
V=60/15
V=4

Where,
E=energy measured in joules
Q=charge measured in coulomb
v=voltage measured in volt

Voltage= no of joules / coulomb.

60/15=4v.

charge=15 voltage=? energy=60
so voltage=energy/charge
i.e.60/15= 4volt.

q=c*v
q is charge,v is voltage,c is capacitence
60=15*v
Hence v=4volt