Electronics - Voltage and Current - Discussion

Discussion Forum : Voltage and Current - General Questions (Q.No. 2)
2.
If 60 J of energy are available for every 15 C of charge, what is the voltage?
4 V
60 V
15 V
0.25 V
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
163 comments Page 12 of 17.

Sourabh sahu said:   1 decade ago
Apply energy is equals to hunkout charge and apply vootage. So e=qV.

SWARNA JHA said:   1 decade ago
As per jouleS formula VOLTAGE=ENERGY/CHARGE SUPPLIED.

V=60/15=4V.

Sridevi said:   1 decade ago
JOULES=VOLT*COULOMB
60=V*15
V=60/15
V=4

Abhinai said:   1 decade ago
V=SQRT OF(2*E/C)

BOOPATHI said:   1 decade ago
E=energy measured in joules.
Q=charge measured in coulomb.
v=voltage measured in volt.

V=60/15
V=4 volt

Anju said:   1 decade ago
The potential difference or voltage, V across two points is defined as energy, E dissipated or transferred by coulomb of charge, Q that moves through the two points.
Therefore:

Potential difference = Electrical energy dissipated
Charge

V= E /Q

V= Voltage
E= Energy
Q= Charge

Bhargav said:   1 decade ago
Joules are volt-coulombs; that is, when you put one coulomb of electrons through a potential difference of 1 volt, you do one joule of work on the system. So you find the number of joules of work (or energy put in to the system) by multiplying the number of coulombs by the number of volts.

Sarath kumar said:   2 decades ago
v = voltage;
e = energy in joules = 60
Q = charge in couloumbs = 15

v = e/q => 60/15
*v = 4;

Mahesh said:   2 decades ago
Voltage is defined as the energy per unit charge.

Arun Jain said:   2 decades ago
E = 1/2 * C * V^2
With the help of this Einsten Eq. the Ans. Should be 8V.
but this is not a option, so we can go through to this way

I= Q/T &........1
P=V*I ,........2
On putting the value of I in equation 2.
P=V*Q/T
E=P*T
E=V*Q/T*T
E=V*Q
V=E/Q
V=60J/15Q
V=4V.


Post your comments here:

Your comments will be displayed after verification.