Electronics - Time Response of Reactive Circuits - Discussion
Discussion Forum : Time Response of Reactive Circuits - Filling the Blanks (Q.No. 8)
8.
If the pulse source has an internal resistance of 80 
in the given circuit, it will take ______ for the output voltage to decrease to zero.
Discussion:
5 comments Page 1 of 1.
Roxy said:
5 years ago
Formula for TC(Time Constant) = L/R.
But since the source has an internal resistance it can be added in series with the 820 Ω resistor.
For the output voltage to decrease to zero it needs 5 Time Constants or simply 5*TC.
Rs = 820 Ω + 80 Ω = 900 Ω,
TC = (200mH/900 Ω) = 222.22μs,
5*TC = (5)(222.22μs) = 1.111ms.
But since the source has an internal resistance it can be added in series with the 820 Ω resistor.
For the output voltage to decrease to zero it needs 5 Time Constants or simply 5*TC.
Rs = 820 Ω + 80 Ω = 900 Ω,
TC = (200mH/900 Ω) = 222.22μs,
5*TC = (5)(222.22μs) = 1.111ms.
Shadan said:
8 years ago
Time constant for RL circuit is;
T= L/R.
200*10^-3/820+80.
= 0.22*10^-3.
so 5*0.22=1.1 ms.
T= L/R.
200*10^-3/820+80.
= 0.22*10^-3.
so 5*0.22=1.1 ms.
Kirito said:
9 years ago
1/5RL just input the given note that R = 820 + 80.
Answer: 1.1ms.
Answer: 1.1ms.
Lavanya said:
8 years ago
Will you please explain how that 1/5RL came?
Indiresh said:
10 years ago
How? I didn't understand.
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