Electronics - Time Response of Reactive Circuits - Discussion

12. 

What is the voltage across the inductor in the given circuit on the falling edge of the first input pulse?

[A]. –0.2 V
[B]. 0.2 V
[C]. –9.8 V
[D]. 9.8 V

Answer: Option A

Explanation:

No answer description available for this question.

Vasu said: (Oct 14, 2011)  
Can anyone explain this please ?

Muddassir said: (Jun 24, 2012)  
Toff= RL=RC.

Ton is given.

T=Toff+Ton.

Ton/T=V (voltage across the inductor).

Put the Value & get the result.

Ramesh said: (May 8, 2015)  
Voltage across inductor VL = vin(1-e^-Rt/L).

R = 50 ohms, L= 300 mH, t = 24 ms.

Vr = VL-Vin.

Meenu said: (Oct 20, 2015)  
Toff = L/R = 6 ms.

Ton = 24 ms.

T = Toff+Ton = 24 ms+6 ms = 30 ms.

VL = Ton/T = 24 ms/30 ms = 0.8.

Vf = Vl-Vin = 0.8-10.0 = -0.2 ms.

Pooja said: (Mar 15, 2016)  
@Meenu 0.8-10.0 = -0.2?

Retsam said: (Jul 27, 2018)  
Why in negative?

Marie said: (Mar 10, 2019)  
VR = Vin(1-(e^(-Rt/L)).
VR = 10(1-(e^(-((24x10^(-3))(50))/(300x10^-3)),
VR = 9.8V,

VL = VR - VIN.
VL = 9.8-10 = -0.2V.

Post your comments here:

Name *:

Email   : (optional)

» Your comments will be displayed only after manual approval.