Electronics - Time Response of Reactive Circuits - Discussion
Discussion Forum : Time Response of Reactive Circuits - General Questions (Q.No. 12)
12.
What is the voltage across the inductor in the given circuit on the falling edge of the first input pulse?
Discussion:
9 comments Page 1 of 1.
Claude said:
4 years ago
No, it should be VL = Vin(e^-Rt/L) since it is an inductor.
Esketit said:
4 years ago
Since it is an inductor, at t=0, VL = Vmax = 10 V. The voltage across the inductor decreases as the current increases opposite of that of the capacitor therefore inductor discharges in the opposite direction thus VL = -Vin^-t/(L/R) = -0.183 = -0.2 V.
(1)
Marie said:
6 years ago
VR = Vin(1-(e^(-Rt/L)).
VR = 10(1-(e^(-((24x10^(-3))(50))/(300x10^-3)),
VR = 9.8V,
VL = VR - VIN.
VL = 9.8-10 = -0.2V.
VR = 10(1-(e^(-((24x10^(-3))(50))/(300x10^-3)),
VR = 9.8V,
VL = VR - VIN.
VL = 9.8-10 = -0.2V.
Retsam said:
7 years ago
Why in negative?
Pooja said:
9 years ago
@Meenu 0.8-10.0 = -0.2?
Meenu said:
10 years ago
Toff = L/R = 6 ms.
Ton = 24 ms.
T = Toff+Ton = 24 ms+6 ms = 30 ms.
VL = Ton/T = 24 ms/30 ms = 0.8.
Vf = Vl-Vin = 0.8-10.0 = -0.2 ms.
Ton = 24 ms.
T = Toff+Ton = 24 ms+6 ms = 30 ms.
VL = Ton/T = 24 ms/30 ms = 0.8.
Vf = Vl-Vin = 0.8-10.0 = -0.2 ms.
Ramesh said:
1 decade ago
Voltage across inductor VL = vin(1-e^-Rt/L).
R = 50 ohms, L= 300 mH, t = 24 ms.
Vr = VL-Vin.
R = 50 ohms, L= 300 mH, t = 24 ms.
Vr = VL-Vin.
Muddassir said:
1 decade ago
Toff= RL=RC.
Ton is given.
T=Toff+Ton.
Ton/T=V (voltage across the inductor).
Put the Value & get the result.
Ton is given.
T=Toff+Ton.
Ton/T=V (voltage across the inductor).
Put the Value & get the result.
Vasu said:
1 decade ago
Can anyone explain this please ?
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