Discussion :: Time Response of Reactive Circuits - General Questions (Q.No.12)
What is the voltage across the inductor in the given circuit on the falling edge of the first input pulse?
Answer: Option A
No answer description available for this question.
|Vasu said: (Oct 14, 2011)|
|Can anyone explain this please ?|
|Muddassir said: (Jun 24, 2012)|
Ton is given.
Ton/T=V (voltage across the inductor).
Put the Value & get the result.
|Ramesh said: (May 8, 2015)|
|Voltage across inductor VL = vin(1-e^-Rt/L).
R = 50 ohms, L= 300 mH, t = 24 ms.
Vr = VL-Vin.
|Meenu said: (Oct 20, 2015)|
|Toff = L/R = 6 ms.
Ton = 24 ms.
T = Toff+Ton = 24 ms+6 ms = 30 ms.
VL = Ton/T = 24 ms/30 ms = 0.8.
Vf = Vl-Vin = 0.8-10.0 = -0.2 ms.
|Pooja said: (Mar 15, 2016)|
|@Meenu 0.8-10.0 = -0.2?|
|Retsam said: (Jul 27, 2018)|
|Why in negative?|
|Marie said: (Mar 10, 2019)|
|VR = Vin(1-(e^(-Rt/L)).
VR = 10(1-(e^(-((24x10^(-3))(50))/(300x10^-3)),
VR = 9.8V,
VL = VR - VIN.
VL = 9.8-10 = -0.2V.
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