Electronics - Time Response of Reactive Circuits - Discussion
Discussion Forum : Time Response of Reactive Circuits - General Questions (Q.No. 6)
6.
In the given circuit, what must the pulse width and time between pulses be to allow the capacitor to completely charge by the end of each pulse and to completely discharge between each pulse?
940 
s
s2.82 ms
3.76 ms
4.7 ms
Discussion:
5 comments Page 1 of 1.
CHARDICE said:
1 decade ago
T = R*C.
= 470 kohm* 0.002 microfarad.
Completion of charging and discharging is equal to 5T.
Time to discharge = 5*470 kohm* 0.002 microfarad.
Answer = 4.7 ms.
= 470 kohm* 0.002 microfarad.
Completion of charging and discharging is equal to 5T.
Time to discharge = 5*470 kohm* 0.002 microfarad.
Answer = 4.7 ms.
Ronan said:
1 decade ago
@Manish.
Capacitor charges and discharges 100% in time which is 5 x RC (always).
Capacitor charges and discharges 100% in time which is 5 x RC (always).
(1)
Bryan said:
1 decade ago
Actually if you calculate that its exactly 4.7.
(1)
Manish lakhiyar said:
1 decade ago
How this come?
5 times RC?
5 times RC?
Tyson Immanuel said:
1 decade ago
T=R*C
=0.940 * 10^-3
(capacitor charges 5 time constant)
Time to discharge = 5 * 0.940 *10^-3
= 4.8ms
(approximately equal to 4.7ms)
=0.940 * 10^-3
(capacitor charges 5 time constant)
Time to discharge = 5 * 0.940 *10^-3
= 4.8ms
(approximately equal to 4.7ms)
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