Discussion :: Time Response of Reactive Circuits - General Questions (Q.No.11)
How long will it take the capacitor in the given circuit to discharge?
Answer: Option D
No answer description available for this question.
|Phaneendra said: (Feb 14, 2011)|
|Vasu said: (Oct 14, 2011)|
|I dint get last two steps. Y are you multiplying toff*5 ?
Whats the correct formula ? anyone please explain ?
|Priya said: (Nov 22, 2011)|
The capacitor will take 5 time constant for fully discharge.
So, 0.0000164*5=0.000082 Sec is equal to 82 µs.
|Maneet said: (Oct 5, 2013)|
|How get time constant = 5?|
|Saheed said: (Dec 4, 2014)|
|5 is the Toff period which will be obtained by .0000164/32.8 = 5.
5 times the RC constant = Charging time.
Post your comments here:
Email : (optional)
» Your comments will be displayed only after manual approval.