Electronics - Time Response of Reactive Circuits - Discussion
Discussion Forum : Time Response of Reactive Circuits - General Questions (Q.No. 1)
1.
What voltage will the capacitor charge up to in the given circuit for the single input pulse shown?
Discussion:
17 comments Page 2 of 2.
Mehta said:
1 decade ago
Elkaa is totally wrong. It takes 5 timeconstant to charge upto Vin.
So it won't charge upto Vin.
Nitesh is right. In that equation substitute t = 32.8us and to = RC = 16.4us.
So it won't charge upto Vin.
Nitesh is right. In that equation substitute t = 32.8us and to = RC = 16.4us.
Ganesh said:
1 decade ago
I agree with elka.
Vasu said:
1 decade ago
Can anyone explain this in brief please.
Nitesh said:
1 decade ago
Vc(voltage across capacitor) = V0(1-e-t/to)
Sreekumar said:
1 decade ago
I agree with Elkaa, it will charge upto Vin.
Elkaa said:
1 decade ago
Dear,
If the timeconstant = RC is 16.4 usec, and the pulse is 32.4 usec, then I would expect that the capacitor charges up to Vin, as it has a lot more time then RC.
Please confirm.
If the timeconstant = RC is 16.4 usec, and the pulse is 32.4 usec, then I would expect that the capacitor charges up to Vin, as it has a lot more time then RC.
Please confirm.
Phaneendra said:
1 decade ago
f=1/RC
Toff=1/f
Ton+Toff=T;32.4+16.2=48.6
Ton/T=Von(drop)
beacause we hav calucalate voltge during on state .
V-Von=4.3v
5-0.66=4.3v
Toff=1/f
Ton+Toff=T;32.4+16.2=48.6
Ton/T=Von(drop)
beacause we hav calucalate voltge during on state .
V-Von=4.3v
5-0.66=4.3v
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