Electronics - Series-Parallel Circuits - Discussion

Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 2)

Series-Parallel Circuits

What is the power dissipated by R2, R4, and R6?

P2 = 417 mW, P4 = 193 mW, P6 = 166 mW

P2 = 407 mW, P4 = 183 mW, P6 = 156 mW

P2 = 397 mW, P4 = 173 mW, P6 = 146 mW

P2 = 387 mW, P4 = 163 mW, P6 = 136 mW

Answer: Option

Explanation:

No answer description is available. Let's discuss.

Discussion:

45 comments Page 5 of 5.

Lara said: 10 years ago

I didn't know how did you find the power for each one?

Jorda said: 10 years ago

Pr2 = Vr2(I1-I2).

I1 = 0.01778 A.
I2 = 0.01058 A.
I3 = 0.00529 A.

= 57.9 V (0.01778 A-0.01058 A).
= 0.417 W.

Pr4 = Vr4 (I2-I3).
Pr6 = Vr6 (I3).

Steve said: 10 years ago

Can you please tell how to get the current in every resistor?

Amit kumar said: 9 years ago

Could you tell how can we find voltage drop when circuit in series.

Hemanth said: 1 decade ago

Can you give description anybody?

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