Electronics - Series-Parallel Circuits - Discussion

Actually mesh analysis is better to get currents and then power.

But it takes so much time.

We have to solve this in the simplest way can anyone tell how to solve this?

Simple solution:-

First find the total resistance of the circuit i.e., 6.25 kiloohm (hope you can find that).
Then find total current i.e., 111/6.25 = 17.73mA.

This current will only flow through 3kiloohm resistor as it is in series with the voltage source.
So the voltage drop across 3kiloohm resistor will be =current through resistor*resistance
=17.73*3 = 53.29 v.

So the voltage at first junction after 3kiloohm resistor is :- 111-53.29=57.79v.
So the voltage across 8kiloohm resistor will be 57.79-0=57.79 v.

We subtract it with zero because the other end of 8kiloohm resistor is at 0 vas it is connected to -ve end of voltage source.

Now power through 8kiloohm resistor is = V(8kiloohm)*V(8kiloohm)/resistance.
=57.79*57.79/8 =417 mW.

SO OPTION A is correct.

For individual resistance, I am getting R2 = 0.01773ohms.

When you do the loop?

how do you get Equation 1: 11kI1-8kI2-111 = 0, where does the 11KI1 come from?

Why the answer is different when we apply v^2/R?

Explain it clearly.

Piease explain clearly.

I can't understand, can someone please elaborate further and use terminologies we all understand kindly?

Can we not apply p = v^2/R?

Very nice answer and question because answer.