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Electronics - Series-Parallel Circuits - Discussion

Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 2)
Series-Parallel Circuits
2.
What is the power dissipated by R2, R4, and R6?

P2 = 417 mW, P4 = 193 mW, P6 = 166 mW
P2 = 407 mW, P4 = 183 mW, P6 = 156 mW
P2 = 397 mW, P4 = 173 mW, P6 = 146 mW
P2 = 387 mW, P4 = 163 mW, P6 = 136 mW
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
45 comments Page 5 of 5.
Ron said:   1 decade ago
Redraw the circuit to it's simplest series form by getting the total resistance and current for the entire circuit then work your way backwards by applying ohm's law to determined the other values.
Priya said:   1 decade ago
In this we use mesh analysis method for current flowing. where have to find

I1=delta1/delta;
I2=delta2/delta;
I3=delta3/delta
Avi said:   1 decade ago
How to determine current in this circuit. Will any body explain ?
Ranjan Singh said:   1 decade ago
First determine the current as I1,I2 and I3.
I1=0.01778A
I2=0.01058A
I3=0.00529A
Now current across R2=0.0072A
" " " R4=0.00529A
" " " R6=0.00529A
By using the formula for power as P=I2R
We will get power across R2=414mW
"""""""""""""""""""""""""R4=196mW
"""""""""""""""""""""""""R6=168mW

So answer will be [A].
Hemanth said:   1 decade ago
Can you give description anybody?
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