Electronics - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 2)
2.
What is the power dissipated by R2, R4, and R6?
Discussion:
45 comments Page 4 of 5.
Jorge said:
1 decade ago
Hello if is possible I would like to see the answer procedure step by step of this exercise. Thank you.
2. What is the power dissipated by R2, R4, and R6?
2. What is the power dissipated by R2, R4, and R6?
Jorge said:
1 decade ago
Hi does anyone can tell me this example step by step?
Arun said:
1 decade ago
By mesh analysis inspection method:
11 I1 - 8 I2 = 111 --> EQN 1.
-8 I1 + 17 I2 - 7 I3= 0 --> EQN 2.
-7 I2 + 14 I3 = 0 --> EQN 3.
BY RESOLVING THESE EQUATIONS WE GET,
I1 = 17.72 mA
I2 = 10.50 mA
I3 = 5.25 mA
Current through R2 is I1-I2 = 7.22 mA.
And by P = (I^2)R formula we can calculate power across the resistor R2
P = 7.22*7.22*10^-6*8*10^3 = 417 mW.
11 I1 - 8 I2 = 111 --> EQN 1.
-8 I1 + 17 I2 - 7 I3= 0 --> EQN 2.
-7 I2 + 14 I3 = 0 --> EQN 3.
BY RESOLVING THESE EQUATIONS WE GET,
I1 = 17.72 mA
I2 = 10.50 mA
I3 = 5.25 mA
Current through R2 is I1-I2 = 7.22 mA.
And by P = (I^2)R formula we can calculate power across the resistor R2
P = 7.22*7.22*10^-6*8*10^3 = 417 mW.
Vinay said:
1 decade ago
Can anybody please tell me what is total current in the circuit and the voltage drop at R2 step by step.
MeghA said:
1 decade ago
Since the voltage drop is same in parallel circuits why can't we take.
P = V^2/R formula.
P = V^2/R formula.
Srikanta roy chowdhury said:
9 years ago
Please explain this clearly.
Mahesh Reddy said:
1 decade ago
We can use this also I think. Please correct me if I am wrong.
P=V2/R. We know that voltage will be same across all the branches i.e. 111.
P=V2/R. We know that voltage will be same across all the branches i.e. 111.
Kim said:
10 years ago
Can somebody explain this step by step with units? So hard to understand this. Sorry guys. With total current, voltage drops, current and power for each resistors.
Kim said:
10 years ago
Guys can somebody explain this step by step like finding required, voltage drops, currents of each resistors and also the power of each things.
REETIKA said:
10 years ago
Please solve this circuit by using ohm's law.
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