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Electronics - Series-Parallel Circuits - Discussion

Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 4)
Series-Parallel Circuits
4.
In a series–parallel circuit, individual component power dissipations are calculated using:
individual component parameters
a percent of the voltage division ratio squared
total current squared multiplied by the resistor values
a percent of the total power depending on resistor ratios
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
1 comments Page 1 of 1.
Neelaji said:   1 decade ago
It will depend upon component parameter because if we take two resistance values are 20 ohms and 100k.power dissipation= v*i
v=i*r
then p=i*i*r
so p is proportional to component parameter
In 20ohms resistor power dissipation less than 100k
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