Electronics - Series-Parallel Circuits - Discussion


In a series–parallel circuit, individual component power dissipations are calculated using:

[A]. individual component parameters
[B]. a percent of the voltage division ratio squared
[C]. total current squared multiplied by the resistor values
[D]. a percent of the total power depending on resistor ratios

Answer: Option A


No answer description available for this question.

Neelaji said: (Feb 4, 2012)  
It will depend upon component parameter because if we take two resistance values are 20 ohms and 100k.power dissipation= v*i
then p=i*i*r
so p is proportional to component parameter
In 20ohms resistor power dissipation less than 100k

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