Electronics - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 11)
11.
What is the total resistance of the given circuit?
92 
288
17.7
128
Discussion:
8 comments Page 1 of 1.
Santhosh said:
3 years ago
How we will get 92? Please explain the answer in detail.
Jerfree Pfundira said:
6 years ago
68+1÷(1/80+1/60+1/80) = 68+24 = 92.
Pari khan said:
8 years ago
1/60+1/80+1/80=24.
Rt=24+68=92.
Rt=24+68=92.
Paresh khatri said:
8 years ago
Good explanation @Shilpa.
@Kushal.
According to your explanation, we can not get this answer (24).
@Kushal.
According to your explanation, we can not get this answer (24).
Kushal soni said:
1 decade ago
1/Rt= (1/80)+(1/60)+(1/80)
= 1/24
Rt= 24
= 1/24
Rt= 24
Oosaravelli said:
1 decade ago
80||60||80 = 24 how ?
Madhusudan said:
1 decade ago
80||60||80=24
and
so tot re=24+68=92
and
so tot re=24+68=92
Shilpa shankar said:
1 decade ago
r2*r4 /r2+r4 = 40
40*r3 /40+r3 =24
Therefore finally series of resultant of those paralle combination with 68 ohm resistance equals to 92 ohms.
40*r3 /40+r3 =24
Therefore finally series of resultant of those paralle combination with 68 ohm resistance equals to 92 ohms.
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