Electronics - Series-Parallel Circuits - Discussion

11. 

What is the total resistance of the given circuit?

[A]. 92 omega.gif
[B]. 288 omega.gif
[C]. 17.7 omega.gif
[D]. 128 omega.gif

Answer: Option A

Explanation:

No answer description available for this question.

Shilpa Shankar said: (Jun 24, 2011)  
r2*r4 /r2+r4 = 40

40*r3 /40+r3 =24

Therefore finally series of resultant of those paralle combination with 68 ohm resistance equals to 92 ohms.

Madhusudan said: (Jul 23, 2011)  
80||60||80=24
and
so tot re=24+68=92

Oosaravelli said: (Feb 4, 2012)  
80||60||80 = 24 how ?

Kushal Soni said: (Jun 26, 2012)  
1/Rt= (1/80)+(1/60)+(1/80)
= 1/24
Rt= 24

Paresh Khatri said: (Sep 16, 2017)  
Good explanation @Shilpa.

@Kushal.

According to your explanation, we can not get this answer (24).

Pari Khan said: (Oct 7, 2017)  
1/60+1/80+1/80=24.

Rt=24+68=92.

Jerfree Pfundira said: (Jan 13, 2020)  
68+1รท(1/80+1/60+1/80) = 68+24 = 92.

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