### Discussion :: Series-Parallel Circuits - General Questions (Q.No.8)

Maddy said: (Apr 18, 2011) | |

May be the answer is 600ohm Plz check someone and explain if answer is 400ohm. |

Swastik said: (Jun 3, 2011) | |

R2 & R3 are in parallel and then in series with R1 Solving, Eq Resistance = 15ohm Then V(given)=21 V So I=V/R=21/15 = 1.4Amp Current across R2(By Current Divider Rule Formula) = 1.4 x 14(R3)/(35+14)= 0.4Amp = 400 mA |

Orange said: (May 23, 2014) | |

By applying mesh analysis at each loop. 40I1-35I2=21---->eqn(1). -35I1+49I2=0----->eqn(2). RESOLVING BOTH WE GET, I1=1.1amp and I2= 1.5amp. current at R2 is I1-I2 =====> 1.5-1.1=0.44amp=400mA. |

James Adams said: (Apr 23, 2015) | |

Where did the 15 ohms come from? |

Jhedd said: (Aug 10, 2015) | |

It is the total resistance. |

Pankaj said: (Aug 12, 2015) | |

1st calculate the total Resistance. Rt = R1+R2||R3. = 5+(35*14)/35+14 = 15. According to voltage divider: Voltage across R1 is V1 = v*R1/Rt. V1=21*5/15=7. Then voltage across the parallel circuit is 21-7=14; Then current across I2 = 14/R2 = 14/35 = 0.4 A or 400 mA. |

Chinmay said: (Feb 20, 2016) | |

I satisfied with your explanation. |

Deepthi said: (Aug 31, 2016) | |

Thanks @Pankaj. |

Happy said: (Sep 15, 2016) | |

Thanks, @Pankaj. Your explanation is very nice. |

P@$Hoo said: (Oct 19, 2016) | |

Nice explanation @Pankaj. |

Kamran said: (Oct 27, 2016) | |

Thanks @Pankaj. |

Lester said: (Dec 17, 2016) | |

Not getting, please explain the solution. |

Tayyab Rehaman said: (Mar 25, 2017) | |

Good explanation, Thanks @Pankaj. |

Manish said: (Apr 13, 2017) | |

If a series"parallel circuit has all 30-ohm resistors, what is the total resistance when R1 is in series with a parallel circuit consisting of R2 and R3? * 45 * 50 * 60 * 90 Please give me the answer. |

Damchi said: (May 23, 2017) | |

Loop1: V =i1(R1+R2) - i2R2. => 21=40i1-35i2 ---------1. Loop2: - i1R1+i2(R2+R3) =0. => - 35i1+49i2=0. => i1=(49/35)i2=(7/5)i2-------2. Solving 1 and 2, i2 = 1 A i1 = 1.4 A. Current through R2 = i1-i2 = 0.4 A = 400 mA. |

Vishal said: (Aug 31, 2018) | |

Nice explanation @Pankaj. |

Gurcharn said: (Feb 1, 2019) | |

I think 600 mA. |

Red said: (Mar 17, 2020) | |

In a circuit, R1 and R2 are connected in series having a resistance of 5 ohms and 10 ohms respectively. The voltage across resistor R1 is equal to 4 V. Find the current passing through R2 and the voltage across the same resistor. Please help. |

Red said: (Mar 17, 2020) | |

A parallel circuit has three branches of 6 ohms, 12 ohms, and 20 ohms. If A of current flows through the 12-ohm branch, what is the current flow through the 20-ohm branch? |

Red said: (Mar 17, 2020) | |

A lamp rated at 120 V, 100 W is to be used on a 220 V line. What size of the resistor should be connected in series with the lamp for correct operation? |

Red said: (Mar 17, 2020) | |

A store lightning system consists of 25 lamps of 100 watts each connected in parallel with 120 V sources. What is the total resistance of this system? |

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