Electronics - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 8)
8.
With 21 V applied, if R1 = 5 ohms, R2 = 35 ohms, and R3 = 14 ohms, what is the current of R2 if R1 is series connected with parallel circuit R2 and R3?
Discussion:
22 comments Page 3 of 3.
Swastik said:
1 decade ago
R2 & R3 are in parallel and then in series with R1
Solving, Eq Resistance = 15ohm
Then V(given)=21 V
So I=V/R=21/15 = 1.4Amp
Current across R2(By Current Divider Rule Formula)
= 1.4 x 14(R3)/(35+14)= 0.4Amp = 400 mA
Solving, Eq Resistance = 15ohm
Then V(given)=21 V
So I=V/R=21/15 = 1.4Amp
Current across R2(By Current Divider Rule Formula)
= 1.4 x 14(R3)/(35+14)= 0.4Amp = 400 mA
(1)
Maddy said:
1 decade ago
May be the answer is 600ohm
Plz check someone and explain if answer is 400ohm.
Plz check someone and explain if answer is 400ohm.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers