Electronics - RLC Circuits and Resonance - Discussion

Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 32)
32.

What is the total current for the nonideal circuit in the given circuit. If it is at resonance?

0 A
284 mu.gif A
3.3 mA
38.5 mA
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
13 comments Page 1 of 2.

Sree said:   1 decade ago
What is meant by nonideal circuit?

Aalya said:   1 decade ago
f=1/2*3.14*sqrt(75*10^-3*0.033*10^-6) = 3.257
Xl = 2*3.14*3.257*75*10^-3 = 1.534
Q = 1.534 / 130 = 0.011
z= 130*(0.011^2 +1) =130.01
i = 5/130.01 = 38.5 mA

Aalya said:   1 decade ago
Q=1/r*sqrtl/c =11.59
z =130(11.59^2+1) =17592.6
I=5/17592.6 = 284.2uA

A BramhaKumar said:   1 decade ago
Whats the basic formula used?

Hoha said:   1 decade ago
At resonance XL - Xc = 0.
Z = sqrt(r2) = r.
I = v/z.

Rrgiri said:   1 decade ago
@Alya : Can't understand z = 130*(0.011^2 +1) = 130.01.

What is it's corresponding formula. Please reply, thanks in advance.

Ritika said:   1 decade ago
The answer should be 38.5 m by using formula v/z.

Emil Lagman said:   1 decade ago
Z = (L/RC).
It = Vs/Z.
= 286 microAmp close enough.

Hima said:   9 years ago
@Aalya.

Is z = R * (Q^2 + 1)? Please tell me, thanks in advance.

Kate said:   8 years ago
Actually you solve this using Q of a practical circuit.
At resonance, Xl = Xc solving for fr,
fr = 1/2pi*sqrt(LC) = 3.2kHz.
Q = Xl/Rs = 2pi(3.2k)(75mH)/130 = 11.6.

Solving for impedance, Z:
Z = Q^2(Rs) = (11.6)^2(130) = 17491.98.

Solving for the total current, It:
It = V/Z = 5/17491.98 = 285.84 uA.
which is almost the same with 284 uA.


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