Electronics - RLC Circuits and Resonance - Discussion
Discussion Forum : RLC Circuits and Resonance - General Questions (Q.No. 32)
32.
What is the total current for the nonideal circuit in the given circuit. If it is at resonance?
0 A
284 
A
A3.3 mA
38.5 mA
Discussion:
13 comments Page 2 of 2.
Najnaj said:
8 years ago
Convert the circuit to the equivalent practical circuit.
fr = 1/2π*√(LC) = 3.2kHz.
Rpractical = ((Rs^2)+(Xl^2)) / Rs = 17612.51 ohms,
since Xl = Xc at resonance,
Z = Rpractical,
Therefore;
5/ Rpractical = 283.88 micro ampere.
fr = 1/2π*√(LC) = 3.2kHz.
Rpractical = ((Rs^2)+(Xl^2)) / Rs = 17612.51 ohms,
since Xl = Xc at resonance,
Z = Rpractical,
Therefore;
5/ Rpractical = 283.88 micro ampere.
Srideepz said:
6 years ago
Resultant current at resonance in parallel circuit I=V÷(L/CR) by sub all values we get I=286micro ampere.
Simpol said:
5 years ago
Leakage current in micro-ampere range.
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